c++ struct size

Posted by kiokko89 on Stack Overflow See other posts from Stack Overflow or by kiokko89
Published on 2011-01-09T16:48:06Z Indexed on 2011/01/09 16:53 UTC
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struct CExample 
{
int a; 
}            

int main(int argc, char* argv[])  
{  

CExample ce;  
CExample ce2;  

cout << "Size:" << sizeof(ce)<< " Address: "<< &ce<< endl;   
cout << "Size:" << sizeof(ce2)<< " Address: "<< &ce2 << endl;   

CExample ceArr[2];
cout << "Size:" << sizeof(ceArr[0])<< " Address: "<<&ceArr[0]<<endl;
cout << "Size:" << sizeof(ceArr[1])<< " Address: "<<&ceArr[1]<<endl;
return 0;
}

Excuse me I'm just a beginner but i'd like to know why with this code, there is a difference of 12 bytes between the addresses of the first two objects(ce and ce2) (i thought about data allignment), but there is only a difference of 4 bytes between the two objects in the array. Sorry for my bad English...

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