Disallow taking pointer/reference to const to a temporary object in C++ (no C++0X)

Posted by KRao on Stack Overflow See other posts from Stack Overflow or by KRao
Published on 2010-11-09T12:36:00Z Indexed on 2011/01/13 14:53 UTC
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Hi, I am faced with the following issue. Consider the following class:

//Will be similar to bost::reference_wrapper
template<class T>
class Ref {
public:
  explicit Ref(T& t) : m_ptr(&t) {}
private:
  T* m_ptr;
};

and this function returning a double

double fun() {return 1.0;}

If we now have

double x = 1.0;
const double xc = 1.0;

Ref<double> ref1(x); //OK
Ref<const double> refc1(cx); //OK

good so far, however:

//Ref<double> ref2( fun() ); //Fails as I want it to
Ref<const double> refc2( fun() ); //Works but I would like it not to

Is there a way to modify Ref (the way you prefer) but not the function fun, so that the last line returns a compile-time error? Please notice you can modify the constructor signature (as long as I am able to initialise the Ref as intended). Thank you in advance for your help!

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