How to write an R function that evaluates an expression within a data-frame

Posted by Prasad Chalasani on Stack Overflow See other posts from Stack Overflow or by Prasad Chalasani
Published on 2011-01-13T16:50:46Z Indexed on 2011/01/13 16:53 UTC
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Puzzle for the R cognoscenti: Say we have a data-frame:

df <- data.frame( a = 1:5, b = 1:5 )

I know we can do things like

with(df, a)

to get a vector of results.

But how do I write a function that takes an expression (such as a or a > 3) and does the same thing inside. I.e. I want to write a function fn that takes a data-frame and an expression as arguments and returns the result of evaluating the expression "within" the data-frame as an environment.

Never mind that this sounds contrived (I could just use with as above), but this is just a simplified version of a more complex function I am writing. I tried several variants ( using eval, with, envir, substitute, local, etc) but none of them work. For example if I define fn like so:

fn <- function(dat, expr) {
  eval(expr, envir = dat)
}

I get this error:

> fn( df, a )
Error in eval(expr, envir = dat) : object 'a' not found

Clearly I am missing something subtle about environments and evaluation. Is there a way to define such a function?

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