The shortest way to convert infix expressions to postfix (RPN) in C

Posted by kuszi on Stack Overflow See other posts from Stack Overflow or by kuszi
Published on 2011-01-06T23:33:28Z Indexed on 2011/01/13 5:54 UTC
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code-golf

Original formulation is given here (you can try also your program for correctness) .

Additional rules:
1. The program should read from standard input and write do standard output.
2. The program should return zero to the calling system/program.
3. The program should compile and run with gcc -O2 -lm -s -fomit-frame-pointer.

The challenge has some history: the call for short implementations has been announced at the Polish programming contest blog in September 2009. After the contest, the shortest code was 81 chars long. Later on the second call has been made for even shorter code and after the year matix2267 published his solution in 78 bytes:

main(c){read(0,&c,1)?c-41&&main(c-40&&(c%96<27||main(c),putchar(c))):exit(0);}

Anyone to make it even shorter or prove this is impossible?

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