Django: DatabaseError column does not exist
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Rosarch
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Published on 2011-01-14T01:46:37Z
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2011/01/14
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I'm having a problem with Django 1.2.4.
Here is a model:
class Foo(models.Model):
# ...
ftw = models.CharField(blank=True)
bar = models.ForeignKey(Bar)
Right after flushing the database, I use the shell:
Python 2.6.6 (r266:84292, Sep 15 2010, 15:52:39)
[GCC 4.4.5] on linux2
Type "help", "copyright", "credits" or "license" for more information.
(InteractiveConsole)
>>> from apps.foo.models import Foo
>>> Foo.objects.all()
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 67, in __repr__
data = list(self[:REPR_OUTPUT_SIZE + 1])
File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 82, in __len__
self._result_cache.extend(list(self._iter))
File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 271, in iterator
for row in compiler.results_iter():
File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/compiler.py", line 677, in results_iter
for rows in self.execute_sql(MULTI):
File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/compiler.py", line 732, in execute_sql
cursor.execute(sql, params)
File "/usr/local/lib/python2.6/dist-packages/django/db/backends/util.py", line 15, in execute
return self.cursor.execute(sql, params)
File "/usr/local/lib/python2.6/dist-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute
return self.cursor.execute(query, args)
DatabaseError: column foo_foo.bar_id does not exist
LINE 1: ...t_omg", "foo_foo"."ftw", "foo_foo...
What am I doing wrong here?
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