python - returns incorrect positive #
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tekknolagi
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Published on 2011-01-15T18:29:27Z
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2011/01/15
18:54 UTC
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what i'm trying to do is write a quadratic equation solver but when the solution should be -1
, as in quadratic(2, 4, 2)
it returns 1
what am i doing wrong?
#!/usr/bin/python import math def quadratic(a, b, c): #a = raw_input("What\'s your `a` value?\t") #b = raw_input("What\'s your `b` value?\t") #c = raw_input("What\'s your `c` value?\t") a, b, c = float(a), float(b), float(c) disc = (b*b)-(4*a*c) print "Discriminant is:\n" + str(disc) if disc >= 0: root = math.sqrt(disc) top1 = b + root top2 = b - root sol1 = top1/(2*a) sol2 = top2/(2*a) if sol1 != sol2: print "Solution 1:\n" + str(sol1) + "\nSolution 2:\n" + str(sol2) if sol1 == sol2: print "One solution:\n" + str(sol1) else: print "No solution!"
EDIT: it returns the following...
>>> import mathmodules >>> mathmodules.quadratic(2, 4, 2) Discriminant is: 0.0 One solution: 1.0
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