How to convert X/Y position to Canvas Left/Top properties when using ItemsControl
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kshahar
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Published on 2011-01-16T21:20:54Z
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2011/01/16
21:53 UTC
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I am trying to use a Canvas to display objects that have "world" location (rather than "screen" location). The canvas is defined like this:
<Canvas Background="AliceBlue">
<ItemsControl Name="myItemsControl" ItemsSource="{Binding MyItems}">
<ItemsControl.ItemTemplate>
<DataTemplate>
<Canvas>
<TextBlock Canvas.Left="{Binding WorldX}" Canvas.Top="{Binding WorldY}"
Text="{Binding Text}"
Width="Auto" Height="Auto" Foreground="Red" />
</Canvas>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
</Canvas>
MyItem is defined like this:
public class MyItem
{
public MyItem(double worldX, double worldY, string text)
{
WorldX = worldX;
WorldY = worldY;
Text = text;
}
public double WorldX { get; set; }
public double WorldY { get; set; }
public string Text { get; set; }
}
In addition, I have a method to convert between world and screen coordinates:
Point worldToScreen(double worldX, double worldY)
{
// return screen coordinates using the canvas properties and an internal MapData object
}
With the current implementation, the items are positioned in the wrong location, because their location is not converted to screen coordinates.
How can I apply the worldToScreen method on the MyItem objects before they are added to the canvas?
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