Make object by it's name
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Ockonal
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Published on 2011-01-16T11:41:44Z
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2011/01/16
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Hello, is it possible to return exemplar of object using passed type name (string) in c++?
I have some base abstract class Base
and a few derivates. Example code:
class Base
{
/* ... */
};
class Der1 : public Base
{
/* ... */
};
class Der2 : public Base
{
/* ... */
};
And I need function like:
Base *objectByType(const std::string &name);
Number of derivates classes are changeable and I don't want to make something like switching of name
and returning by hands new object type. Is it possible in c++ to do that automatically anyway?
p.s. usage should looks like:
dynamic_cast<Der1>(objectByType("Der1"));
I need pure c++ code (crossplatform). Using boost is permissible.
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