Typedef equivalence in function arguments
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Warren Seine
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Published on 2011-01-17T22:49:22Z
Indexed on
2011/01/17
22:53 UTC
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Hi guys,
The question is kind of hard to ask without an example so here it is:
#include <vector>
struct O
{
};
struct C
{
template <typename T>
void function1(void (C::*callback)(const O*));
template <typename T>
void function2(void (C::*callback)(const typename T::value_type));
void print(const O*);
};
int main()
{
C c;
c.function1< std::vector<O*> >(&C::print); // Success.
c.function2< std::vector<O*> >(&C::print); // Fail.
}
The error that I am given is:
error: no matching function for call to ‘C::function2(void (C::*)(const O*))’
.
Basically, the only difference between calls is that in function2
, I'm more generic since I use the typedef std::vector<O*>::value_type
which should resolve to O*
, hence similar to function1
.
I'm using G++ 4.2.1 (I know it's old), but Comeau confirms I'm wrong.
Why does the compilation fail?
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