jQuery ajax return value
Posted
by
Jordan Pagaduan
on Stack Overflow
See other posts from Stack Overflow
or by Jordan Pagaduan
Published on 2011-02-13T07:19:33Z
Indexed on
2011/02/13
7:25 UTC
Read the original article
Hit count: 253
How can I return the value "pinNumber" from jquery ajax so I can append it outside of the ajax. Here is my code
var x = pinLast + 1;
for(i=x;i<=pinMany;i++) {
var i = x++;
var cardNumber = i.toPrecision(8).split('.').reverse().join('');
var pinNumber = '';
jQuery.ajax({
type: "POST",
url: "data.php",
data: "request_type=generator",
async: false,
success: function(msg){
var pinNumber = msg;
return pinNumber;
//pin number should return
}
});
jQuery('.pin_generated_table').append(cardNumber+' = '+pinNumber+'
');
// the variable pinNumber should be able to go here
}
Please ask me if you don't understand.. ^^ thanks
© Stack Overflow or respective owner