How to grep 2 or 3 lines, one containing the text I want, and the others just below it?

Posted by Kaustubh P on Ask Ubuntu See other posts from Ask Ubuntu or by Kaustubh P
Published on 2011-02-24T06:02:54Z Indexed on 2011/02/24 7:32 UTC
Read the original article Hit count: 289

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bash

|

shell

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grep

This is a snapshot of error log:

06:16:29,933 ERROR EmailRMManager$:45 - Exception In get Message
com.rabbitmq.client.AlreadyClosedException: clean connection shutdown; reason: Attempt to use closed channel
    at com.rabbitmq.client.impl.AMQChannel.ensureIsOpen(AMQChannel.java:195)
    at com.rabbitmq.client.impl.AMQChannel.rpc(AMQChannel.java:222)
    at com.rabbitmq.client.impl.AMQChannel.rpc(AMQChannel.java:208)
    at com.rabbitmq.client.impl.AMQChannel.exnWrappingRpc(AMQChannel.java:139)
    at com.rabbitmq.client.impl.ChannelN.basicGet(ChannelN.java:645)

I do the following command:

cat foo.log | grep ERROR to get an OP as:

06:16:29,933 ERROR EmailRMManager$:45 - Exception In get Message

What command should I execute to get the output as

06:16:29,933 ERROR EmailRMManager$:45 - Exception In get Message
    com.rabbitmq.client.AlreadyClosedException: clean connection shutdown; reason: Attempt to use closed channel

ie, also grep the line(s) after the pattern?

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