php SimpleCassie Cassandra TimeUUID

Posted by chnet on Stack Overflow See other posts from Stack Overflow or by chnet
Published on 2011-03-18T12:56:53Z Indexed on 2011/03/19 0:10 UTC
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I created a column family Users using following command:

create column family Users with comparator=TimeUUIDType and default_validation_class=UTF8Type;

Then I insert a column into Users. It shows as follows.

RowKey: jsmith

=>(column=66829930-515b-11e0-8443-0f82b246fa40, value=hello, timestamp=1300451382)

I want to access it using SimpleCassie. The command is:

$data = $cassie->keyspace('Keyspace1')->cf('Users')->key('jsmith')->column('66829930-515b-11e0-8443-0f82b246fa40')->value();

(I also tried: $data = $cassie->keyspace('Keyspace1')->cf('Users')->key('jsmith')->column($cassie->uuid('66829930-515b-11e0-8443-0f82b246fa40')->__toString())->value();)

However, They do not work. It always return NULL. How can I get the column value (hello) I want?

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