SciPy interp1d results are different than MatLab interp1

Posted by LMO on Stack Overflow See other posts from Stack Overflow or by LMO
Published on 2011-11-21T16:53:27Z Indexed on 2011/11/21 17:50 UTC
Read the original article Hit count: 276

Filed under:
|
|

I'm converting a MatLab program to Python, and I'm having problems understanding why scipy.interpolate.interp1d is giving different results than MatLab interp1.

In MatLab the usage is slightly different:

yi = interp1(x,Y,xi,'cubic')

SciPy:

f = interp1d(x,Y,kind='cubic')
yi = f(xi)

For a trivial example the results are the same: MatLab:

interp1([0 1 2 3 4], [0 1 2 3 4],[1.5 2.5 3.5],'cubic')
  1.5000 2.5000 3.5000

Python:

interp1d([1,2,3,4],[1,2,3,4],kind='cubic')([1.5,2.5,3.5])
  array([ 1.5,  2.5,  3.5])

But for a real-world example they are not the same:

x =   0.0000e+000  2.1333e+001  3.2000e+001  1.6000e+004  2.1333e+004  2.3994e+004
Y =   -6   -6   20   20   -6   -6
xi =  0.00000 11.72161 23.44322 35.16484...  (2048 data points)

Matlab:

-6.0000e+000
-1.2330e+001
-3.7384e+000
  ...
 7.0235e+000
 7.0028e+000
 6.9821e+000

SciPy:

array([[ -6.00000000e+00],
       [ -1.56304101e+01],
       [ -2.04908267e+00],
       ..., 
       [  1.64475576e+05],
       [  8.28360759e+04],
       [ -5.99999999e+00]])

Any thoughts as to how to can get results that are consistent with MatLab?

© Stack Overflow or respective owner

Related posts about python

Related posts about matlab