Executing an exe with arguments using Powershell

Posted by Chris Charge on Stack Overflow See other posts from Stack Overflow or by Chris Charge
Published on 2011-11-23T20:42:41Z Indexed on 2011/11/24 1:50 UTC
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powershell

This is what I want to execute:

c:\Program Files (x86)\SEQUEL ViewPoint\viewpoint.exe /Setvar((POSTSTR $POSTSTR)(POSTEND $POSTEND)) /G:C:\viewpointfile.vpt /D:C:($BEGDATE to $TODDATE).xls

This is what I have tried:

$a = "/Setvar((POSTSTR $POSTSTR)(POSTEND $POSTEND))"

$b = "/G:C:\viewpointfile.vpt"

$c = "/D:C:($BEGDATE to $TODDATE).xls"

$Viewpoint = "c:\Program Files (x86)\SEQUEL ViewPoint\viewpoint.exe"

&$Viewpoint $a $b $c

When I execute this I receive an error stating:

File C:\viewpointfile.vpt "/D:C:($BEGDATE to $TODDATE).xls" not found!

I'm not sure where it gets the extra quotes from. If I run the command with just $a and $b it runs fine.

Any help would be greatly appreciated. Thanks! :)

Update

manojlds suggested echoargs so here it the output from it:

&./echoargs.exe $viewpoint $a $b $c

Arg 0 is C:\Program Files (x86)\SEQUEL ViewPoint\viewpoint.exe

Arg 1 is /Setvar((POSTSTR 20101123)(POSTEND 20111123))

Arg 2 is /G:C:\viewpointfile.vpt

Arg 3 is /D:C:(2010-11-23 to 2011-11-23 PM).xls

It appears that all the arguments are being passed properly. When I run this as a command in cmd.exe it executes perfectly. So something on Powershells end must be messing up the output.

Is there any other way to go about executing this command using Powershell?

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