PHP Pass Dynamic Array name to function
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by
Brad
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Published on 2012-03-29T23:02:30Z
Indexed on
2012/03/29
23:29 UTC
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How do I pass an array key to a function to pull up the right key's data?
// The array
<?php
$var['TEST1'] = Array (
'Description' => 'This is a Description',
'Version' => '1.11',
'fields' => Array(
'ID' => array(
'type' => 'int',
'length' =>'11',
'misc' =>'auto_increment'
),
'DATA' => array(
'type' => 'varchar', '
length' => '255'
)
);
$var['TEST2'] = Array (
'Description' =? 'This is the 2nd Description',
'Version' => '2.1',
'fields' => Array(
'ID' => array(
'type' => 'int',
'length' =>'11',
'misc' =>'auto_increment'
),
'DATA' => array(
'type' => 'varchar', '
length' => '255'
)
)
// The function
<?php
$obj = 'TEST1';
print_r($schema[$obj]); // <-- Fives me output. But calling the function doesn't.
echo buildStructure($obj);
/**
* @TODO to add auto_inc support
*/
function buildStructure($obj)
{
$output = '';
$primaryKey = $schema["{$obj}"]['primary key'];
foreach ($schema["{$obj}"]['fields'] as $name => $tag)
// #### ERROR #### Invalid argument supplied for foreach()
{
$type = $tag['type'];
$length = $tag['length'];
$default = $tag['default'];
$description = $tag['description'];
$length = (isset($length)) ? "({$length})" : '';
$default = ($default == NULL ) ? "NULL" : $default;
$output .= "`{$name}` {$type}{$length} DEFAULT {$default} COMMENT `{$DESCRIPTION}`, ";
}
return $output;
}
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