SQL Query That Should Return Least two days record
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Published on 2012-04-13T05:05:53Z
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I have a table "abc" where i store timestamp having multiple records let suppose
1334034000 Date:10-April-2012
1334126289 Date:11-April-2012
1334291399 Date:13-April-2012
I want to build a sql query where I can find at first attempt the records having last two day values and so second time the next two days . . .
Example:
Select *,dayofmonth(FROM_UNIXTIME(i_created)) from notes
where dayofmonth(FROM_UNIXTIME(i_created)) > dayofmonth(FROM_UNIXTIME(i_created)) -2
order by dayofmonth(FROM_UNIXTIME(i_created))
this query returns all the records date wise but we need very most two days record.
Please suggest accordingly. Thanks in advance
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