C code Error: free(): invalid next size (fast):
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Published on 2012-06-04T21:49:48Z
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2012/06/04
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I got an error from my code, but I'm not sure where to fix it.
Here's the explanation of what my code does:
I'm writing some code that will read an input file and store each line as an object (char type) in an array. The first line of the input file is a number. This number tells me how many lines that I should read and store in the array. Here's my code:
int main(int argc, char *argv[]){
FILE *fp;
char **path;
int num, i;
...
/*after reading the first line and store the number value in num*/
path = malloc(num *sizeof(char));
i=0;
while (!feof(fp)) {
char buffer[500];
int length = 0;
for (ch = fgetc(fp); ch != EOF && ch != '\n'; ch = fgetc(fp)) {
buffer[length++] = ch;
}
if(ch == '\n' && ch!= EOF){
buffer[length] = '\0';
path[i] = malloc(strlen(buffer)+1);
strcpy(path[i], buffer);
i++;
}
}
...
free(path);
}
After running the code, I get this
*** glibc detected *** free(): invalid next size (fast):
I have searched around and know this is malloc/free error, but I don't exactly know to fix it. Any help would be great. Thanks!
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