RBG to CbyCr conversion code

Posted by user1446688 on Stack Overflow See other posts from Stack Overflow or by user1446688
Published on 2012-06-09T21:41:38Z Indexed on 2012/06/09 22:40 UTC
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I am wondering why this code does not work. Basically it is supposed to convert between RGB and CbYCr. When I convert from RGB to CbYCr then back to RGB I do not get the original RGB values. What is wrong with this code?

#define MIN(a,b) (((a)<(b))?(a):(b)) #define MAX(a,b) (((a)>(b))?(a):(b))

struct _rgb { int R; int G; int B; };

typedef struct _rgb rgb;

struct _cbycr { int Cb; int Y; int Cr; };

typedef struct _cbycr cbycr;

void cbycr2rgb(rgb *c, double Y, double Cb, double Cr) { int r = (int)(Y + 1.40200 * (Cr - 0x80)); int g = (int)(Y - 0.34414 * (Cb - 0x80) - 0.71414 * (Cr - 0x80)); int b = (int)(Y + 1.77200 * (Cb - 0x80)); c->R = MAX(0, MIN(255, r)); c->G = MAX(0, MIN(255, g)); c->B = MAX(0, MIN(255, b)); }

void rgb2cbycr(cbycr *c, int R, int G, int B) { c->Y = (int)(0.299 * R + 0.587 * G + 0.114 * B); c->Cb = (int)(-0.16874 * R - 0.33126 * G + 0.50000 * B); c->Cr =(int)(0.50000 * R - 0.41869 * G - 0.08131 * B); }

int main() { cbycr _cbycr; rgb _rgb; _rgb.R = 50; _rgb.G = 50; _rgb.B = 50; rgb2cbycr(&_cbycr, _rgb.R, _rgb.G, _rgb.B); cbycr2rgb(&_rgb, _cbycr.Y, _cbycr.Cb, _cbycr.Cr); printf("rgb=%d %d %d\n", _rgb.R, _rgb.G, _rgb.B); return 0; }

output: rgb=0 185 0

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