Been searching around for a bit and cannot find a solution for this one. I guess I'm looking for a leaf-directory by name. In this example I'd like to get a list of directories call 'modules' that do NOT have a subdirectory called module.

modules/package1/modules/spackage1
modules/package1/modules/spackage2
modules/package1/modules/spackage3/modules
modules/package1/modules/spackage3/modules/spackage1
modules/package2/modules/

The list I desire would contain

modules/package1/modules/spackage3/modules/
modules/package2/modules/

All the directories named module that do not have a subdirectory called module

I started with trying something this with no luck

find . -name modules \! -exec sh -c 'find -name modules' \;

-exec works on exit code, okay lets pass the count as exit code

find . -name modules -exec sh -c 'exit $(find {} -name modules|grep -n ""|tail -n1|cut -d: -f1)' \;

This should take the count of each subdirectory called modules and exit with it. No such love.