How to create a dynamically built Context Menu clickEvent

Posted by Chris on Stack Overflow See other posts from Stack Overflow or by Chris
Published on 2012-06-20T13:59:04Z Indexed on 2012/06/20 15:16 UTC
Read the original article Hit count: 228

Filed under:
|

C#, winform

I have a DataGridView and a context menu that opens when you right click a specific column. What shows up in the context menu is dependant on what's in the field clicked on - paths to multiple files (the paths are manipulated to create a full UNC path to the correct file).

The only problem is that I can't get the click working. I did not drag and drop the context menu from the toolbar, I created it programmically.

I figured that if I can get the path (let's call it ContextMenuChosen) to show up in MessageBox.Show(ContextMenuChosen); I could set the same to System.Diagnostics.Process.Start(ContextMenuChosen);

The Mydgv_MouseUp event below actually works to the point where I can get it to fire off MessageBox.Show("foo!"); when something in the context menu is selected but that's where it ends. I left in a bunch of comments below showing what I've tried when it one of the paths are clicked. Some result in empty strings, others error (Object not set to an instance...).

I searched code all day yesterday but couldn't find another way to hook up a dynamically built Context Menu clickEvent.

Code and comments:

    ContextMenu m = new ContextMenu();

    // SHOW THE RIGHT CLICK MENU
    private void Mydgv_MouseClick(object sender, MouseEventArgs e)
    {
        if (e.Button == MouseButtons.Right)
        {
            int currentMouseOverCol = Mydgv.HitTest(e.X, e.Y).ColumnIndex;
            int currentMouseOverRow = Mydgv.HitTest(e.X, e.Y).RowIndex;

            if (currentMouseOverRow >= 0 && currentMouseOverCol == 6)
            {
                string[] paths = myPaths.Split(';');
                foreach (string path in paths)
                {
                    string UNCPath = "\\\\1.1.1.1\\c$\\MyPath\\";
                    string FilePath = path.Replace("c:\\MyPath\\", @"");
                    m.MenuItems.Add(new MenuItem(UNCPath + FilePath));
                }
            }
            m.Show(Mydgv, new Point(e.X, e.Y));
        }
    }



    // SELECTING SOMETHING IN THE RIGHT CLICK MENU
    private void Mydgv_MouseUp(object sender, MouseEventArgs e)
    {
        DataGridView.HitTestInfo hitTestInfo;
        if (e.Button == MouseButtons.Right)
        {
            hitTestInfo = Mydgv.HitTest(e.X, e.Y);
            // If column is first column
            if (hitTestInfo.Type == DataGridViewHitTestType.Cell && hitTestInfo.ColumnIndex == 6)
            {
                //MessageBox.Show(m.ToString());
                ////MessageBox.Show(m.Tag.ToString());
                //MessageBox.Show(m.Name.ToString());
                //MessageBox.Show(m.MenuItems.ToString());
                ////MessageBox.Show(m.MdiListItem.ToString());
                // MessageBox.Show(m.Name);
                //if (m.MenuItems.Count > 0)
                //MessageBox.Show(m.MdiListItem.Text);
                //MessageBox.Show(m.ToString());
                //MessageBox.Show(m.MenuItems.ToString());
                //Mydgv.ContextMenu.Show(m.Name.ToString());
                //MessageBox.Show(ContextMenu.ToString());
                //MessageBox.Show(ContextMenu.MenuItems.ToString());
                //MenuItem.text
                //MessageBox.Show(this.ContextMenu.MenuItems.ToString());

            }

            m.MenuItems.Clear();
        }

    }

I'm very close to completing this so any help would be much appreciated.

Thanks,

~ Chris

© Stack Overflow or respective owner

Related posts about c#

Related posts about winforms