How to make c# don't call destructor of a instance
Posted
by
Bình Nguyên
on Stack Overflow
See other posts from Stack Overflow
or by Bình Nguyên
Published on 2012-06-26T17:07:29Z
Indexed on
2012/06/27
3:16 UTC
Read the original article
Hit count: 183
I have two forms and form1
needs to get data from form2
, i use a parameter in form2
constructor to gets form1's
instance like this:
public form2(Form form1) {
this.f = form1;
}
and in form1:
Form form2 = new Form(this);
But it seem form1 destruct was called when i closed form1. my question is how can i avoid this problem?
EDIT: I have many typing mistakes in my question, i'm so sorry, fixed:
I have two forms and form2
needs to get data from form1
, i use a parameter in form1
constructor to gets form1's
instance like this:
private Form f;
public form2(Form form1) {
this.f = form1;
}
and in form1:
Form form2 = new Form(this);
But it seem form1 destruct was called when i closed form2. my question is how can i avoid this problem?
© Stack Overflow or respective owner