Explicit constructor still has default values even though a default constructor is not invoked.
Posted
by
Phoenix
on Stack Overflow
See other posts from Stack Overflow
or by Phoenix
Published on 2012-08-29T03:12:36Z
Indexed on
2012/08/29
3:38 UTC
Read the original article
Hit count: 150
java
According to my understanding a default constructor initializes the state of the object to default values, so if i provide an explicit no-arg public constructor like this then how are the values of d and e still getting initialized to zero because in this case the default constructor is not invoked.
public class B extends A{
private int d;
private int e;
public B() {
System.out.println(d);
System.out.println(e);
}
}
EDIT:: The only thing default constructor does is call to super()
then how come if i have a explicitly mentioned a constructor here and A has a protected variable say c which is initialized to 17 in its constructor. Should I not be explicitly calling super()
to be able to see that change since I'm using my own constructor ? Why is B still getting the value of 17 through inheritance ?
© Stack Overflow or respective owner