BASH function not escaping control characters

Posted by ehime on Super User See other posts from Super User or by ehime
Published on 2012-08-31T19:14:27Z Indexed on 2012/08/31 21:40 UTC
Read the original article Hit count: 370

Hey guys I have a function that I'm using to find stuff, but unfortunately anytime I pass it a control character ($intVal or testing : etc) it chokes. I was wondering what the fix was?

I can understand that using $ or % or : etc in grep without escaping causes this issue, but since I'm passing it in by reference I'm not sure how to escape it...

Anyway, here's the code.

function ffind()
{
     if [ $1 ] ; then
         find -type f | grep -ir '$1' * | grep -v '.svn'
     else
         echo "'$1' is not a valid resource"
     fi
}

Example(s):

$ ffind $intVal
'' is not a valid resource

$ ffind "testing :"
bash: [: testing: unary operator expected
'testing :' is not a valid resource

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