Strange behaviour of CUDA kernel
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Published on 2012-08-22T16:22:16Z
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2012/08/31
3:38 UTC
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cuda
I'm writing code for calculating prefix sum. Here is my kernel
__global__ void prescan(int *indata,int *outdata,int n,long int *sums)
{
extern __shared__ int temp[];
int tid=threadIdx.x;
int offset=1,start_id,end_id;
int *global_sum=&temp[n+2];
if(tid==0)
{
temp[n]=blockDim.x*blockIdx.x;
temp[n+1]=blockDim.x*(blockIdx.x+1)-1;
start_id=temp[n];
end_id=temp[n+1];
//cuPrintf("Value of start %d and end %d\n",start_id,end_id);
}
__syncthreads();
start_id=temp[n];
end_id=temp[n+1];
temp[tid]=indata[start_id+tid];
temp[tid+1]=indata[start_id+tid+1];
for(int d=n>>1;d>0;d>>=1)
{
__syncthreads();
if(tid<d)
{
int ai=offset*(2*tid+1)-1;
int bi=offset*(2*tid+2)-1;
temp[bi]+=temp[ai];
}
offset*=2;
}
if(tid==0)
{
sums[blockIdx.x]=temp[n-1];
temp[n-1]=0;
cuPrintf("sums %d\n",sums[blockIdx.x]);
}
for(int d=1;d<n;d*=2)
{
offset>>=1;
__syncthreads();
if(tid<d)
{
int ai=offset*(2*tid+1)-1;
int bi=offset*(2*tid+2)-1;
int t=temp[ai];
temp[ai]=temp[bi];
temp[bi]+=t;
}
}
__syncthreads();
if(tid==0)
{
outdata[start_id]=0;
}
__threadfence_block();
__syncthreads();
outdata[start_id+tid]=temp[tid];
outdata[start_id+tid+1]=temp[tid+1];
__syncthreads();
if(tid==0)
{
temp[0]=0;
outdata[start_id]=0;
}
__threadfence_block();
__syncthreads();
if(blockIdx.x==0 && threadIdx.x==0)
{
for(int i=1;i<gridDim.x;i++)
{
sums[i]=sums[i]+sums[i-1];
}
}
__syncthreads();
__threadfence();
if(blockIdx.x==0 && threadIdx.x==0)
{
for(int i=0;i<gridDim.x;i++)
{
cuPrintf("****sums[%d]=%d ",i,sums[i]);
}
}
__syncthreads();
__threadfence();
if(blockIdx.x!=gridDim.x-1)
{
int tid=(blockIdx.x+1)*blockDim.x+threadIdx.x;
if(threadIdx.x==0)
cuPrintf("Adding %d \n",sums[blockIdx.x]);
outdata[tid]+=sums[blockIdx.x];
}
__syncthreads();
}
In above kernel, sums array will accumulate prefix sum per block and and then first thread will calculate prefix sum of this sum array. Now if I print this sum array from device side it'll show correct results while in
cuPrintf("Adding %d \n",sums[blockIdx.x]);
this line it prints that it is taking old value. What could be the reason?
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