If I define a property to prototype appears in the constructor of object, why?
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Eduard Florinescu
on Programmers
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Published on 2012-09-10T20:48:39Z
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2012/09/10
21:49 UTC
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I took the example from this question modified a bit: What is the point of the prototype method?
function employee(name,jobtitle,born)
{
this.name=name;
this.jobtitle=jobtitle;
this.born=born;
this.status="single"
}
employee.prototype.salary=10000000;
var fred=new employee("Fred Flintstone","Caveman",1970);
console.log(fred.salary);
fred.salary=20000;
console.log(fred.salary)
And the output in console is this:
What is the difference salary
is in constructor but I still can access it with fred.salary
, how can I see if is in constructor from code, status is still employee property how can I tell for example if name
is the one of employee or has been touch by initialization?
Why is salary in constructor, when name,jobtitle,born where "touched" by employee("Fred Flintstone","Caveman",1970);
«constructor»?
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