i am trying to write code to determine the nature of input using if statement only. The nature of input could be following:

• a multiple of 11
• even or odd.

For the code below, when I enter my input, it does not display the result as "input:NOT:ODD". Also how can I check multiple conditions with if statement? (else is not considered)

import java.util.Scanner;
public class test
{
    public static void main( String args[] )
    {
        Scanner input = new Scanner( System.in );
        int x;
        int EO;
        int Mult;
        System.out.print ( "Enter value: " );
        x = input.nextInt();
        EO = x % 2;
        Mult = x % 11;
        if (EO > 0 && Mult > 0)
        {
            System.out.printf ("%d:NOT:ODD");
        }
    }
}