Reference and Value confusion

Posted by rgamber on Stack Overflow See other posts from Stack Overflow or by rgamber
Published on 2012-10-03T03:31:15Z Indexed on 2012/10/03 3:37 UTC
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Hi I read this question on Stack overflow, and tried to do an example.

I had the below code:

public static void main(String[] args){
     int i = 5;
     Integer I = new Integer(5);

     increasePrimitive(i);
     increaseObject(I);

     System.out.println(i); //Prints 5 - correct
     System.out.println(I); //Still prints 5
     System.out.println(increaseObject2(I)); //Still prints 5

}

public static void increasePrimitive(int n){
     n++;
}

public static void increaseObject(Integer n){
     n++;
}

public static int increaseObject2(Integer n){
         return n++; 
}

Does the increaseObject print 5 because the value of reference is changing inside that function? Am I right? I am confused why the increasedObject2 prints 5 and not 6.

Can anyone please explain?

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