Wireshark WPA 4-way handshake
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cYrus
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Published on 2012-04-16T20:37:52Z
Indexed on
2012/10/07
15:40 UTC
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From this wiki page:
WPA and WPA2 use keys derived from an EAPOL handshake to encrypt traffic. Unless all four handshake packets are present for the session you're trying to decrypt, Wireshark won't be able to decrypt the traffic. You can use the display filter eapol to locate EAPOL packets in your capture.
I've noticed that the decryption works with (1, 2, 4) too, but not with (1, 2, 3). As far as I know the first two packets are enough, at least for what concern unicast traffic. Can someone please explain exactly how does Wireshark deal with that, in other words why does only the former sequence work, given that the fourth packet is just an acknowledgement? Also, is it guaranteed that the (1, 2, 4) will always work when (1, 2, 3, 4) works?
Test case
This is the gzipped handshake (1, 2, 4) and an ecrypted ARP
packet (SSID: SSID
, password: password
) in base64
encoding:
H4sICEarjU8AA2hhbmRzaGFrZS5jYXAAu3J400ImBhYGGPj/n4GhHkhfXNHr37KQgWEqAwQzMAgx 6HkAKbFWzgUMhxgZGDiYrjIwKGUqcW5g4Ldd3rcFQn5IXbWKGaiso4+RmSH+H0MngwLUZMarj4Rn S8vInf5yfO7mgrMyr9g/Jpa9XVbRdaxH58v1fO3vDCQDkCNv7mFgWMsAwXBHMoEceQ3kSMZbDFDn ITk1gBnJkeX/GDkRjmyccfus4BKl75HC2cnW1eXrjExNf66uYz+VGLl+snrF7j2EnHQy3JjDKPb9 3fOd9zT0TmofYZC4K8YQ8IkR6JaAT0zIJMjxtWaMmCEMdvwNnI5PYEYJYSTHM5EegqhggYbFhgsJ 9gJXy42PMx9JzYKEcFkcG0MJULYE2ZEGrZwHIMnASwc1GSw4mmH1JCCNQYEF7C7tjasVT+0/J3LP gie59HFL+5RDIdmZ8rGMEldN5s668eb/tp8vQ+7OrT9jPj/B7425QIGJI3Pft72dLxav8BefvcGU 7+kfABxJX+SjAgAA
Decode with:
$ base64 -d | gunzip > handshake.cap
Run tshark
to see if it correctly decrypt the ARP
packet:
$ tshark -r handshake.cap -o wlan.enable_decryption:TRUE -o wlan.wep_key1:wpa-pwd:password:SSID
It should print:
1 0.000000 D-Link_a7:8e:b4 -> HonHaiPr_22:09:b0 EAPOL Key 2 0.006997 HonHaiPr_22:09:b0 -> D-Link_a7:8e:b4 EAPOL Key 3 0.038137 HonHaiPr_22:09:b0 -> D-Link_a7:8e:b4 EAPOL Key 4 0.376050 ZyxelCom_68:3a:e4 -> HonHaiPr_22:09:b0 ARP 192.168.1.1 is at 00:a0:c5:68:3a:e4
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