Distinguishing repetitive code with the same implementation
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KyelJmD
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Published on 2012-10-22T02:02:34Z
Indexed on
2012/10/22
5:15 UTC
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Hit count: 578
Given this sample code
import java.util.ArrayList;
import blackjack.model.items.Card;
public class BlackJackPlayer extends Player {
private double bet;
private Hand hand01 = new Hand();
private Hand hand02 = new Hand();
public void addCardToHand01(Card c) {
hand01.addCard(c);
}
public void addCardToHand02(Card c) {
hand02.addCard(c);
}
public void bustHand01() {
hand01.setBust(true);
}
public void bustHand02() {
hand02.setBust(true);
}
public void standHand01() {
hand01.setStand(true);
}
public void standHand02() {
hand02.setStand(true);
}
public boolean isHand01Bust() {
return hand01.isBust();
}
public boolean isHand02Bust() {
return hand02.isBust();
}
public boolean isHand01Standing() {
return hand01.isStanding();
}
public boolean isHand02Standing() {
return hand02.isStanding();
}
public int getHand01Score(){ return hand01.getCardScore(); }
public int getHand02Score(){ return hand02.getCardScore(); }
}
Is this considered as a repetitive code? providing that each method is operating a seperate field but doing the same implementation ? Note that hand01 and hand02 should be distinct.
if this is considered as repetitive code, how would I address this? providing that each hand is a seperate entity
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