python mock side_effect or return_value dependent on call_count

Posted by user18380 on Stack Overflow See other posts from Stack Overflow or by user18380
Published on 2012-11-13T10:19:48Z Indexed on 2012/11/13 11:01 UTC
Read the original article Hit count: 178

Filed under:
|

To test a polling function I want to mock the calling of a sub function so that the first time it is called it will fail, and the second time it is called it will succeed. Here's a very simplified version of it:

poll_function(var1):
    value = sub_function(var1)  # First call will return None
    while not value:
        time.sleep(POLLING_INTERVAL)  
        value = sub_function(var1) # A subsequent call will return a string, e.g "data"
    return value

Is this possible to do with a Mock object from the mock framework? I know Mock objects have a call_count attribute I should be able to use somehow.

Right now I've solved it by creating a custom mock object that I use to monkey patch sub_function(), but I feel there should be a better less verbose way of doing it:

def test_poll():
    class MyMock(object):                                                      

        def __init__(self, *args):                                             
            self.call_count = 0                                                

        def sub_function(self, *args, **kwargs):                             
            if self.call_count > 1:                                            
                return "data"            
            else:                                                              
                self.call_count += 1                                           
                return None  

    my_mock = MyMock()                                                         
    with patch('sub_function', my_mock.sub_function):           
        ok_(poll_function())         

© Stack Overflow or respective owner

Related posts about python

Related posts about mocking