How to fill a structure when a pointer to it, is passed as an argument to a function
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Ram
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Published on 2012-11-14T04:57:08Z
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2012/11/14
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I have a function:
func (struct passwd* pw)
{
struct passwd* temp;
struct passwd* save;
temp = getpwnam("someuser");
/* since getpwnam returns a pointer to a static
* data buffer, I am copying the returned struct
* to a local struct.
*/
if(temp) {
save = malloc(sizeof *save);
if (save) {
memcpy(save, temp, sizeof(struct passwd));
/* Here, I have to update passed pw* with this save struct. */
*pw = *save; /* (~ memcpy) */
}
}
}
The function which calls func(pw) is able to get the updated information.
But is it fine to use it as above. The statement *pw = *save is not a deep copy. I do not want to copy each and every member of structure one by one like pw->pw_shell = strdup(save->pw_shell) etc.
Is there any better way to do it?
Thanks.
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