How to loop an array with strings as indexes in PHP

Posted by Axel Lambregts on Stack Overflow See other posts from Stack Overflow or by Axel Lambregts
Published on 2012-11-25T16:49:15Z Indexed on 2012/11/25 17:04 UTC
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I had to make an array with as indexes A-Z (the alphabet). Each index had to have a value 0. So i made this array:

$alfabet = array(
'A' => 0,
'B' => 0,
'C' => 0,
'D' => 0,
'E' => 0,
'F' => 0,
'G' => 0,
'H' => 0,
'I' => 0,
'J' => 0,
'K' => 0,
'L' => 0,
'M' => 0,
'N' => 0,
'O' => 0,
'P' => 0,
'Q' => 0,
'R' => 0,
'S' => 0,
'T' => 0,
'U' => 0,
'V' => 0,
'W' => 0,
'X' => 0,
'Y' => 0,
'Z' => 0
);

I also have got text from a file ($text = file_get_contents('tekst15.txt');) I have putted the chars in that file to an array: $textChars = str_split ($text); and sorted it from A-Z: sort($textChars);

What i want is that (with a for loop) when he finds an A in the textChars array, the value of the other array with index A, goes up by one (so like: $alfabet[A]++;

Can anyone help me with this loop? I have this atm:

for($i = 0; $i <= count($textChars); $i++){

while($textChars[$i] == $alfabet[A]){
$alfabet[A]++;
}


}
echo $alfabet[A];

Problem 1: i want to loop the alfabet array to, so now i only check for A but i want to check all indexes. Problem2: this now returns 7 for each alphabet index i try so its totally wrong :)

I'm sorry about my english but thanks for your time.

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