storing passed arguments in separate variables -shell scripting

Posted by Nathan Pk on Stack Overflow See other posts from Stack Overflow or by Nathan Pk
Published on 2012-12-13T22:47:58Z Indexed on 2012/12/13 23:03 UTC
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bash

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shell

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argument-passing

In my script "script.sh" , I want to store 1st and 2nd argument to some variable and rest to another separate variable. What command I must use to implement this task? Number of arguments that is passed to a script is random)

When I run the command in console

./script.sh abc def ghi jkl mn o p qrs xxx   #It can have any number of arguments

In this case, I want my script to store "abc" and "def" in one variable. "ghi jkl mn o p qrs xxx" should be stored in another variable.

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