find: missing argument to -exec in bash script
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Mephi_stofel
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Published on 2012-12-20T10:35:51Z
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2012/12/20
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The following works fine when I type it exactly in the command line:
find /<some_path>/{epson,epson_laser,epson_inkjet} -iname "*.ppd"
-exec grep "\*ModelName\:" {} \; | sed 's/.*\"\(.*\)\"/\1/'
However, when I try to call the following from a
bash script I get find: missing argument to -exec'.
I have also tried the following (in many variants):
eval find "$1" -iname "*.ppd" -exec 'bash -c grep "\*ModelName\:" "$1" | sed "s/.*\"\(.*\)\"/\1/" \;
as was mentioned in find-exec-echo-missing-argument-to-exec.
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