TCP video streaming: TCP throughput(rate) and RTT
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misteryes
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Published on 2013-07-02T22:58:55Z
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we know that a rough estimation of TCP rate is: WINDOW/RTT, where WINDOW
is the min(CWIN, RWIN), CWIN is the congestion window size of the sender, while RWIN is the receiving window.
nowadays, the encoding rate of videos may be 1000KB/s(8000kbit/s), if RTT is 500ms, it needs the window size to be 2000KB. But we know that usually the receiving window size is below 64KB, there is a big gap.
so if RTT is too large, TCP streaming is not possible?
Is my understanding right?
thanks!
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