I want to get the Modify date of a file and then format it into a human readable date. I am running a C program that gets information on when a particular file was last modified. My C Code contains a sytem cmd which contains a number of egreps, awks, seds separated by pipes. Using sed or awk or something similar, how can I convert 06 to June (This can be any month so an array or something is required) What I am trying to achieve is to end up with a string similar to:

My C code contains:

    char string1[100] = "";
    #define MAXCHAR 100
    FILE *fp;
    char str[MAXCHAR], str2[MAXCHAR];
    char* filename = "newfile";

    /*
    stat: run 'stat' on the dtlName file to display status information.
    egrep: search for the pattern 'Modify' and print the lines containing it.
    awk: Get columns 2 & 3
    sed: replace the . with a space, leaving 3 columns of output
    awk: only print cols 1 & 2 to newfile
    sed: replace '-' with ' ' in newfile
    awk: format output in newfile
    */
    sprintf(string1, "/bin/stat %s  \
                    | egrep Modify \
                    | /bin/awk '{print $2, $3}' \
                    | /bin/sed 's/\\./ /g' \
                    | /bin/awk '{print $1, $2}' \
                    | /bin/sed 's/-/ /g' \
                    | /bin/awk '{print $3,$2\", \"$1,\"at\",$4}' > newfile"
                    , dtlName);
    system(string1);
    fp = fopen(filename, "r");
    while (fgets(str, MAXCHAR, fp) != NULL)
            sprintf(str2,"%s", str);

    /*  Write information to file */
    DisplayReportFile (report);
    ReportEntry (report,L"Source file: %s, Created: %s\n\n",dtlName,str2);