What am I encrypting wrong here?
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Katie Krueger
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Published on 2013-10-22T20:14:17Z
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2013/10/22
21:54 UTC
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So I have a wordplay project to do and I have to encrypt some characters. I am at the point where I am stuck, and when I run it and type 1 for encrypt it doesn't shift that many letters. It just prints the work over again. I am wondering what I could do to fix it where if I say "hello" it will print 1 character over and say "ifmmp" Thank you!
import java.util.Scanner;
public class WordPlayTester{
public static void main(String [] args){
String word, reverse="";
String original;
int key= 0;
String Menu= "1-Encrypt \n2-Decrypt \n3-Is Palindrome \n0-Quit \n-Select an option-";
Scanner in = new Scanner(System.in);
System.out.println("-Type any word-");
word = in.nextLine();
System.out.println(Menu);
int choice=in.nextInt();
if(choice==1)
{
System.out.println("Insert a Key number");
int select= in.nextInt();
for (int i=0; i < word.length(); i++) {
char c = word.charAt(i);
if (c >= 'A' && c <= 'Z') {
c = (char)(c - 64);
int n = c+1;
n = n % 26;
if (n < 0) {
n = n + 26;
}
c = (char)(n + 65);
}
System.out.println(c);
}
}
else if(choice==3)
{
int length = word.length();
for ( int i = length - 1 ; i >= 0 ; i-- )
reverse = reverse + word.charAt(i);
if (word.equals(reverse))
System.out.println("Your word is a palindrome.");
else
System.out.println("Your word is not a palindrome.");
}
else if(choice==0)
{
System.exit(0);
}
else
{
System.out.println(Menu);
}
}
}
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