Sorting a Singly Linked List With Pointers
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Mark Simson
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Published on 2013-10-24T03:34:07Z
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2013/10/24
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I am trying to sort a singly linked list using bubble sort by manipulating ONLY the pointers, no keys.
The following gets stuck in the for loop and loops infinitely. I don't understand why this is. Can anybody explain to me why the end of the list is not being found?
Node* sort_list(Node* head)
{
Node * temp;
Node * curr;
for(bool didSwap = true; didSwap; ) {
didSwap = false;
for(curr = head; curr->next != NULL; curr = curr->next) {
if(curr->key > curr->next->key) {
temp = curr;
curr = curr->next;
curr->next = temp;
didSwap = true;
}
cout << curr->next->key << endl;
}
}
return head;
}
If I change the code so that the keys (data) are swapped, then the function works properly but for some reason I am not able make it work by manipulating only pointers.
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