Order a sentence alphabetically and count the number of times each words appears and print in a table

Posted by JaAnTr on Stack Overflow See other posts from Stack Overflow or by JaAnTr
Published on 2013-10-25T09:34:02Z Indexed on 2013/10/25 9:54 UTC
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I am struggling with the print in a table part of the question. So far I have managed to order the user inputted sentence alphabetically and count the number of times each word occurs. Here is the code:

thestring = (raw_input())
sentence = thestring.split(" ")
sentence.sort()

count = {}
for word in thestring.split():
    try: count[word] += 1
    except KeyError: count[word] = 1

print sentence
print count

And when I run the code I get this:

['apple', 'apple', 'banana', 'mango', 'orange', 'pear', 'pear', 'strawberry']
{'apple': 2, 'pear': 2, 'strawberry': 1, 'mango': 1, 'orange': 1, 'banana': 1}

However, ideally I want it printed in a table that looks something like:

apple.....|.....2
banana....|.....1
mango.....|.....1
orange....|.....1
pear......|.....2
strawberry|.....1

Thanks for any help!

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