I have the following sample code and I wanted to know the correct way to get access to the Pass method in the CBar class. Currently I have found 3 ways to get access to this method and they are as follows:

1. Casting the object, ((CBar *) &foo)->Pass(1, 2, 3);
2. Using this syntax, foo.CBar::Pass(1,2,3);
3. Use the "using" syntax in the CFoo class declaration, using CBar::Pass.

The following is an example of a simple project to test this capability.

Foo.h

#include "bar.h"
class CFoo :
    public CBar
{
private:
    double m_a;
    double m_b;
public:
    CFoo(void);
    ~CFoo(void);

    void Pass(double a, double b);
};

Foo.cpp

#include "Foo.h"
CFoo::CFoo(void)
{
    m_a = 0.0;
    m_b = 0.0;
}
CFoo::~CFoo(void)
{
}

void CFoo::Pass(double a, double b)
{
    m_a = a;
    m_b = b;
}

Bar.h

class CBar
{
    int m_x;
    int m_y;
    int m_z;
public:
CBar(void);
~CBar(void);

void Pass(int x, int y, int z);
};

Bar.cpp

#include "Bar.h"

CBar::CBar(void)
{
    m_x = 0;
    m_y = 0;
    m_z = 0;
}

CBar::~CBar(void)
{
}

void CBar::Pass(int x, int y, int z)
{
    m_x = x;
    m_y = y;
    m_z = z;
}

And my main class DoStuff.cpp

#include "DoStuff.h"
#include "Foo.h"

CDoStuff::CDoStuff(void)
{
}

CDoStuff::~CDoStuff(void)
{
}

int main()
{
    CFoo foo, foo1, foo2;

    //This only gets to the Pass method in Foo.
    foo.Pass(2.5, 3.5);

    //Gets access to Pass method in Bar.
    foo1.CBar::Pass(5,10,15);

    //Can also case and access by location for the same result??
    ((CBar *) &foo2)->Pass(100,200,300);

    return 0;
}

Are each of these options viable? Are some preferred? Are there pitfalls with using any one of the methods listed?

I am especially curious about the foo.CBar::Pass(1,2,3) syntax.

Thanks,

B