Comparing char for validation in C++

Posted by Corey Starbird on Stack Overflow See other posts from Stack Overflow or by Corey Starbird
Published on 2013-11-01T03:50:38Z Indexed on 2013/11/01 3:53 UTC
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 /*
 PROGRAM: Ch6_14.cpp
 Written by Corey Starbird
 This program calculates the balance
 owed to a hospital for a patient.
 Last modified: 10/28/13
 */

#include <iostream>
#include <fstream>
#include <iomanip>
#include <string>
using namespace std;

// Prototypes for In-patient and Out-patient functions.
double stayTotal (int, double, double, double); // For In-patients
double stayTotal (double, double);              // For Out-patients

int main()
{

    char    patientType;        // In-patient (I or i) or Out-patient (O or o)
    double  rate,               // Daily rate for the In-patient stay
    servCharge,                 // Service charge for the stay
    medCharge,                  // Medication charge for the stay
    inTotal,                    // Total for the In-patient stay
    outTotal;                   // Total for the Out-patient stay
    int     days;               // Number of days for the In-patient stay

    // Find out if they were an In-patient or an Out-patient
    cout << "Welcome, please enter (I) for an In-patient or (O) for an Out-patient:" << endl;
    cin >> patientType;
    while (patientType != 'I' || 'i' || 'O' || 'o')
    {
        cout << "Invalid entry. Please enter either (I) for an In-patient or (O) for an Out-patient:" << endl;
        cin >> patientType;
    }



    cout << "FIN";

    return 0;
}

Hey, brand new to C++ here. I am working on a project and I'm having trouble figuring out why my validation for patientTypeisn't working properly. I first had double quotes, but realized that would denote strings. I changed them to single quotes, my program will compile and run now, but the while loop runs no matter what I enter, I, i, O, o, or anything else.

I don't know why the while loop isn't checking the condition, seeing that I did enter one of the characters in the condition, and move on to cout. Probably a simple mistake, but I thank you in advance.

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