I'm trying to figure out exactly what is going on with the following assembly code. Can someone go down line by line and explain what is happening? I input what I think is happening (see comments) but need clarification.

        .file   "testcalc.c"
        .section        .rodata.str1.1,"aMS",@progbits,1
.LC0:
        .string "x=%d, y=%d, z=%d, result=%d\n"
        .text
.globl main
        .type   main, @function
main:
        leal    4(%esp), %ecx   // establish stack frame
        andl    $-16, %esp      // decrement %esp by 16, align stack
        pushl   -4(%ecx)     // push original stack pointer
        pushl   %ebp     // save base pointer
        movl    %esp, %ebp     // establish stack frame 
        pushl   %ecx         // save to ecx
        subl    $36, %esp      // alloc 36 bytes for local vars
        movl    $11, 8(%esp)     // store 11 in z
        movl    $6, 4(%esp)      // store 6 in y 
        movl    $2, (%esp)    // store 2 in x
        call    calc         // function call to calc
        movl    %eax, 20(%esp)  // %esp + 20 into %eax
        movl    $11, 16(%esp)  // WHAT
        movl    $6, 12(%esp)  // WHAT
        movl    $2, 8(%esp)  // WHAT
        movl    $.LC0, 4(%esp)  // WHAT?!?!
        movl    $1, (%esp) // move result into address of %esp
        call    __printf_chk  // call printf function
        addl    $36, %esp  // WHAT?
        popl    %ecx 
        popl    %ebp
        leal    -4(%ecx), %esp
        ret
        .size   main, .-main
        .ident  "GCC: (Ubuntu 4.3.3-5ubuntu4) 4.3.3"
        .section        .note.GNU-stack,"",@progbits

Original code:

#include <stdio.h>

int calc(int x, int y, int z);

int main()
{
        int x = 2;
        int y = 6;
        int z = 11;
        int result;

        result = calc(x,y,z);

        printf("x=%d, y=%d, z=%d, result=%d\n",x,y,z,result);
}