Ajax div can't access address bar variable
Posted
by
Elaine Adams
on Stack Overflow
See other posts from Stack Overflow
or by Elaine Adams
Published on 2013-11-07T21:52:20Z
Indexed on
2013/11/07
21:53 UTC
Read the original article
Hit count: 225
Can someone please advise me on how my Ajax div can get an address bar variable. The usual way just doesn't work.
My address bar currently looks like this:
http://localhost/social3/browse/?locationName=Cambridge
Usually, I would use a little php and do this:
$searchResult = $_POST['locationName'];
echo $searchResult;
But because I'm in an Ajax div, I can't seem to get to the variable.
Do I need to add some JavaScript wizardry to my Ajax coding? (I have little knowledge of this)
My Ajax:
<script>
window.onload = function () {
var everyone = document.getElementById('everyone'),
searching = document.getElementById('searching'),
searchingSubmit = document.getElementById('searchingSubmit');
everyone.onclick = function() {
loadXMLDoc('indexEveryone');
everyone.className = 'filterOptionActive';
searching.className = 'filterOption';
}
searching.onclick = function() {
loadXMLDoc('indexSearching');
searching.className = 'filterOptionActive';
everyone.className = 'filterOption';
}
searchingSubmit.onclick = function() {
loadXMLDoc('indexSearchingSubmit');
}
function loadXMLDoc(pageName)
{
var xmlhttp;
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("leftCont").innerHTML=xmlhttp.responseText;
}
}
function get_query(){
var url = location.href;
var qs = url.substring(url.indexOf('?') + 1).split('&');
for(var i = 0, result = {}; i < qs.length; i++){
qs[i] = qs[i].split('=');
result[qs[i][0]] = decodeURIComponent(qs[i][1]);
}
return result;
}
xmlhttp.open("GET","../browse/" + pageName + ".php?user=" + get_query()['user'],true);
xmlhttp.send();
}
}
</script>
<!-- ends ajax script -->
© Stack Overflow or respective owner