Why does this Bash regex match return an Exit Status of "2"?
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PreservedMoose
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Published on 2014-05-27T03:21:08Z
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2014/05/27
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I'm writing a Bash script that needs to scan for the existence of non-ASCII characters in filenames. I'm using the POSIX bracket regex syntax to match the non-ASCII characters, but for some reason, when I test for the match in an if/then statement, the test always returns an Exit Status of 2, and never matches my test string.
Here's the code in question:
FILEREQ_SOURCEFILE="Filename–WithNonAScII-Charàcters-05sec_23.98.mov"
REGEX_MATCH_NONASCII="[^[:ascii:]]"
if [[ $FILEREQ_SOURCEFILE =~ $REGEX_MATCH_NONASCII ]]; then
echo "Exit Status: $?"
echo "Matched!"
else
echo "Exit Status: $?"
echo "No Match"
fi
This code always returns:
Exit Status: 2
No Match
I've read and re-read the bash-hackers.org explanation of how regex matching works, as well as this previous question on SO regarding matching non-ASCII characters, but for the life of me, I can't get this to work. What am I missing here?
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