Why is forwarding variadic parameters invalid?
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Published on 2014-06-04T21:15:21Z
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2014/06/04
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swift-language
|variadic-functions
Consider the variadic function parameter:
func foo(bar:Int...) -> () { }
Here foo
can accept multiple arguments, eg foo(5,4)
. I am curious about the type of Int...
and its supported operations. For example, why is this invalid?
func foo2(bar2:Int...) -> () {
foo(bar2);
}
Gives a error:
Could not find an overload for '_conversion' that accepts the supplied arguments
Why is forwarding variadic parameters invalid?
What is the "conversion" the compiler is complaining about?
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