Conversion from C code to CudaC code I get unpredictable results

Posted by Abhi on Stack Overflow See other posts from Stack Overflow or by Abhi
Published on 2014-06-07T11:14:39Z Indexed on 2014/06/08 9:25 UTC
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include

include

include

include

define pi 3.14159265359

lo*lo*p-2*mu,freq=2.25*1e6,wavelength=(long double)lo/freq,dh=(long double)wavelength/

30.0,dt=(long double)dh/(lo*1.5);

(1000*dh));

(p*dh),lambdaplus2mudtbydh=(lambda+2*mu)*dt/dh,lambdadtbydh=lambda*dt/dh,dtmubydh=dt*mu/

dh;

double**U,long double**V){

for(int k=0,l=0;k<=yno-1 && l<=yno;k++,l++){

U[i+1][l]+=dtbyrhodh*(X[i+1][l+1]-X[i+1][l]+Z[i+1][l]-

Z[i][l]);

[k+1]-Y[j][k+1]);

}

double**U,long double**V){

for(int k=0,l=0;k<=yno-1 && l<=yno;k++,l++){

U[i+1][k])+lambdadtbydh*(V[i+1][k+1]-V[i][k+1]);

V[i][k+1])+lambdadtbydh*(U[i+1][k+1]-U[i+1][k]);

U[j][l]);

int main(){

clock_t start,end;

long double time_taken;

start=clock();

long double **X,**Y,**U,**V,**Z;int n=1;

X=Make2DDoubleArray(xno+2,yno+2);

Y=Make2DDoubleArray(xno+2,yno+2);

Z=Make2DDoubleArray(xno+1,yno+1);

U=Make2DDoubleArray(xno+2,yno+2);

V=Make2DDoubleArray(xno+2,yno+2);

for (n=1;n<=timesteps;n++){

}

end=clock();

time_taken=(long double)(end-start)/CLOCKS_PER_SEC;

printf("Time elapsed is %Lf\nGRID Size:%Lf*%Lf\nTime Steps

Taken:%d\n",time_taken,(xno),floor(yno),n);

return 0;

}

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