codility challenge, test case OK , Evaluation report Wrong Answer
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Hussein Fawzy
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Published on 2014-06-08T22:07:09Z
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2014/06/10
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the aluminium 2014 gives me wrong answer [3 , 9 , -6 , 7 ,-3 , 9 , -6 , -10] got 25 expected 28
but when i repeated the challenge with the same code and make case test it gives me the correct answer
Your test case [3, 9, -6, 7, -3, 9, -6, -10] : NO RUNTIME ERRORS (returned value: 28)
what is the wrong with it ???
the challenge :-
A non-empty zero-indexed array A consisting of N integers is given. A pair of integers (P, Q), such that 0 = P = Q < N, is called a slice of array A. The sum of a slice (P, Q) is the total of A[P] + A[P+1] + ... + A[Q]. The maximum sum is the maximum sum of any slice of A. For example, consider array A such that: A[0] = 3 A[1] = 2 A[2] = -6 A[3] = 3 A[4] = 1 For example (0, 1) is a slice of A that has sum A[0] + A[1] = 5. This is the maximum sum of A. You can perform a single swap operation in array A. This operation takes two indices I and J, such that 0 = I = J < N, and exchanges the values of A[I] and A[J]. To goal is to find the maximum sum you can achieve after performing a single swap. For example, after swapping elements 2 and 4, you will get the following array A: A[0] = 3 A[1] = 2 A[2] = 1 A[3] = 3 A[4] = -6 After that, (0, 3) is a slice of A that has the sum A[0] + A[1] + A[2] + A[3] = 9. This is the maximum sum of A after a single swap. Write a function: class Solution { public int solution(int[] A); } that, given a non-empty zero-indexed array A of N integers, returns the maximum sum of any slice of A after a single swap operation. For example, given: A[0] = 3 A[1] = 2 A[2] = -6 A[3] = 3 A[4] = 1 the function should return 9, as explained above.
and my code is :-
import java.math.*;
class Solution {
public int solution(int[] A) {
if(A.length == 1)
return A[0];
else if (A.length==2)
return A[0]+A[1];
else{
int finalMaxSum = A[0];
for (int l=0 ; l<A.length ; l++){
for (int k = l+1 ; k<A.length ; k++ ){
int [] newA = A;
int temp = newA[l];
newA [l] = newA[k];
newA[k]=temp;
int maxSum = newA[0];
int current_max = newA[0];
for(int i = 1; i < newA.length; i++)
{
current_max = Math.max(A[i], current_max + newA[i]);
maxSum = Math.max(maxSum, current_max);
}
finalMaxSum = Math.max(finalMaxSum , maxSum);
}
}
return finalMaxSum;
}
}
}
i don't know what's the wrong with it ??
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