Use of .apply() with 'new' operator. Is this possible?
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by
Premasagar
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Published on 2009-10-22T12:15:09Z
Indexed on
2014/06/12
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In JavaScript, I want to create an object instance (via the new
operator), but pass an arbitrary number of arguments to the constructor. Is this possible?
What I want to do is something like this (but the code below does not work):
function Something(){
// init stuff
}
function createSomething(){
return new Something.apply(null, arguments);
}
var s = createSomething(a,b,c); // 's' is an instance of Something
The Answer
From the responses here, it became clear that there's no in-built way to call .apply()
with the new
operator. However, people suggested a number of really interesting solutions to the problem.
My preferred solution was this one from Matthew Crumley (I've modified it to pass the arguments
property):
var createSomething = (function() {
function F(args) {
return Something.apply(this, args);
}
F.prototype = Something.prototype;
return function() {
return new F(arguments);
}
})();
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