How does * work in Python
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Deqing
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Published on 2014-08-23T04:17:51Z
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2014/08/23
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Just switched from C++ to Python, and found that sometimes it is a little hard to understand ideas behind Python.
I guess, a variable is a reference to the real object. For example, a=(1,2,5) meaning a -> (1,2,5), so if b=a, then b and a are 2 references pointing to the same (1,2,5). It is a little like pointers in C/C++.
If I have:
def foo(a,b,c):
print a,b,c
a=(1,3,5)
foo(*a)
What does *
mean here?
Looks like it expands tuple a to a[0], a[1] and a[2]. But why print(*a)
is not working while print(a[0],a[1],a[2])
works fine?
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