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• Color drop down in Excel cell (with no text)? e.g. bgcolor = Red-Green-Amber-unknown

  - by adolf garlic

  I have an Excel sheet that I'm using to keep track of the status of certain things. I want to have a column which consists of cells containing a repeated drop down that allows you to select (as background) red amber green unknown I don't want any text in this cell, I just want a coloured block. Is this possible? I've tried playing around with data-validation-list (based on range containing all of said colours but to no avail)

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• Auditing front end performance on web application

  - by user1018494

  I am currently trying to performance tune the UI of a company web application. The application is only ever going to be accessed by staff, so the speed of the connection between the server and client will always be considerably more than if it was on the internet. I have been using performance auditing tools such as Y Slow! and Google Chrome's profiling tool to try and highlight areas that are worth targeting for investigation. However, these tools are written with the internet in mind. For example, the current suggestions from a Google Chrome audit of the application suggests is as follows: Network Utilization Combine external CSS (Red warning) Combine external JavaScript (Red warning) Enable gzip compression (Red warning) Leverage browser caching (Red warning) Leverage proxy caching (Amber warning) Minimise cookie size (Amber warning) Parallelize downloads across hostnames (Amber warning) Serve static content from a cookieless domain (Amber warning) Web Page Performance Remove unused CSS rules (Amber warning) Use normal CSS property names instead of vendor-prefixed ones (Amber warning) Are any of these bits of advice totally redundant given the connection speed and usage pattern? The users will be using the application frequently throughout the day, so it doesn't matter if the initial hit is large (when they first visit the page and build their cache) so long as a minimal amount of work is done on future page views. For example, is it worth the effort of combining all of our CSS and JavaScript files? It may speed up the initial page view, but how much of a difference will it really make on subsequent page views throughout the working day? I've tried searching for this but all I keep coming up with is the standard internet facing performance advice. Any advice on what to focus my performance tweaking efforts on in this scenario, or other auditing tool recommendations, would be much appreciated.

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• Enum driving a Visual State change via the ViewModel

  - by Chris Skardon

  Exciting title eh? So, here’s the problem, I want to use my ViewModel to drive my Visual State, I’ve used the ‘DataStateBehavior’ before, but the trouble with it is that it only works for bool values, and the minute you jump to more than 2 Visual States, you’re kind of screwed. A quick search has shown up a couple of points of interest, first, the DataStateSwitchBehavior, which is part of the Expression Samples (on Codeplex), and also available via Pete Blois’ blog. The second interest is to use a DataTrigger with GoToStateAction (from the Silverlight forums). So, onwards… first let’s create a basic switch Visual State, so, a DataObj with one property: IsAce… public class DataObj : NotifyPropertyChanger { private bool _isAce; public bool IsAce { get { return _isAce; } set { _isAce = value; RaisePropertyChanged("IsAce"); } } } The ‘NotifyPropertyChanger’ is literally a base class with RaisePropertyChanged, implementing INotifyPropertyChanged. OK, so we then create a ViewModel: public class MainPageViewModel : NotifyPropertyChanger { private DataObj _dataObj; public MainPageViewModel() { DataObj = new DataObj {IsAce = true}; ChangeAcenessCommand = new RelayCommand(() => DataObj.IsAce = !DataObj.IsAce); } public ICommand ChangeAcenessCommand { get; private set; } public DataObj DataObj { get { return _dataObj; } set { _dataObj = value; RaisePropertyChanged("DataObj"); } } } Aaaand finally – hook it all up to the XAML, which is a very simple UI: A Rectangle, a TextBlock and a Button. The Button is hooked up to ChangeAcenessCommand, the TextBlock is bound to the ‘DataObj.IsAce’ property and the Rectangle has 2 visual states: IsAce and NotAce. To make the Rectangle change it’s visual state I’ve used a DataStateBehavior inside the Layout Root Grid: <i:Interaction.Behaviors> <ei:DataStateBehavior Binding="{Binding DataObj.IsAce}" Value="true" TrueState="IsAce" FalseState="NotAce"/> </i:Interaction.Behaviors> So now we have the button changing the ‘IsAce’ property and giving us the other visual state: Great! So – the next stage is to get that to work inside a DataTemplate… Which (thankfully) is easy money. All we do is add a ListBox to the View and an ObservableCollection to the ViewModel. Well – ok, a little bit more than that. Once we’ve got the ListBox with it’s ItemsSource property set, it’s time to add the DataTemplate itself. Again, this isn’t exactly taxing, and is purely going to be a Grid with a Textblock and a Rectangle (again, I’m nothing if not consistent). Though, to be a little jazzy I’ve swapped the rectangle to the other side (living the dream). So, all that’s left is to add some States to the template.. (Yes – you can do that), these can be the same names as the others, or indeed, something else, I have chosen to stick with the same names and take the extra confusion hit right on the nose. Once again, I add the DataStateBehavior to the root Grid element: <i:Interaction.Behaviors> <ei:DataStateBehavior Binding="{Binding IsAce}" Value="true" TrueState="IsAce" FalseState="NotAce"/> </i:Interaction.Behaviors> The key difference here is the ‘Binding’ attribute, where I’m now binding to the IsAce property directly, and boom! It’s all gravy!   So far, so good. We can use boolean values to change the visual states, and (crucially) it works in a DataTemplate, bingo! Now. Onwards to the Enum part of this (finally!). Obviously we can’t use the DataStateBehavior, it' only gives us true/false options. So, let’s give the GoToStateAction a go. Now, I warn you, things get a bit complex from here, instead of a bool with 2 values, I’m gonna max it out and bring in an Enum with 3 (count ‘em) 3 values: Red, Amber and Green (those of you with exceptionally sharp minds will be reminded of traffic lights). We’re gonna have a rectangle which also has 3 visual states – cunningly called ‘Red’, ‘Amber’ and ‘Green’. A new class called DataObj2: public class DataObj2 : NotifyPropertyChanger { private Status _statusValue; public DataObj2(Status status) { StatusValue = status; } public Status StatusValue { get { return _statusValue; } set { _statusValue = value; RaisePropertyChanged("StatusValue"); } } } Where ‘Status’ is my enum. Good times are here! Ok, so let’s get to the beefy stuff. So, we’ll start off in the same manner as the last time, we will have a single DataObj2 instance available to the Page and bind to that. Let’s add some Triggers (these are in the LayoutRoot again). <i:Interaction.Triggers> <ei:DataTrigger Binding="{Binding DataObject2.StatusValue}" Value="Amber"> <ei:GoToStateAction StateName="Amber" UseTransitions="False" /> </ei:DataTrigger> <ei:DataTrigger Binding="{Binding DataObject2.StatusValue}" Value="Green"> <ei:GoToStateAction StateName="Green" UseTransitions="False" /> </ei:DataTrigger> <ei:DataTrigger Binding="{Binding DataObject2.StatusValue}" Value="Red"> <ei:GoToStateAction StateName="Red" UseTransitions="False" /> </ei:DataTrigger> </i:Interaction.Triggers> So what we’re saying here is that when the DataObject2.StatusValue is equal to ‘Red’ then we’ll go to the ‘Red’ state. Same deal for Green and Amber (but you knew that already). Hook it all up and start teh project. Hmm. Just grey. Not what I wanted. Ok, let’s add a ‘ChangeStatusCommand’, hook that up to a button and give it a whirl: Right, so the DataTrigger isn’t picking up the data on load. On the plus side, changing the status is making the visual states change. So. We’ll cross the ‘Grey’ hurdle in a bit, what about doing the same in the DataTemplate? <Codey Codey/> Grey again, but if we press the button: (I should mention, pressing the button sets the StatusValue property on the DataObj2 being represented to the next colour). Right. Let’s look at this ‘Grey’ issue. First ‘fix’ (and I use the term ‘fix’ in a very loose way): The Dispatcher Fix This involves using the Dispatcher on the View to call something like ‘RefreshProperties’ on the ViewModel, which will in turn raise all the appropriate ‘PropertyChanged’ events on the data objects being represented. So, here goes, into turdcode-ville – population – me: First, add the ‘RefreshProperties’ method to the DataObj2: internal void RefreshProperties() { RaisePropertyChanged("StatusValue"); } (shudder) Now, add it to the hosting ViewModel: public void RefreshProperties() { DataObject2.RefreshProperties(); if (DataObjects != null && DataObjects.Count > 0) { foreach (DataObj2 dataObject in DataObjects) dataObject.RefreshProperties(); } } (double shudder) and now for the cream on the cake, adding the following line to the code behind of the View: Dispatcher.BeginInvoke(() => ((MoreVisualStatesViewModel)DataContext).RefreshProperties()); So, what does this *ahem* code give us: Awesome, it makes the single bound data object show the colour, but frankly ignores the DataTemplate items. This (by the way) is the same output you get from: Dispatcher.BeginInvoke(() => ((MoreVisualStatesViewModel)DataContext).ChangeStatusCommand.Execute(null)); So… Where does that leave me? What about adding a button to the Page to refresh the properties – maybe it’s a timer thing? Yes, that works. Right, what about using the Loaded event then eh? Loaded += (s, e) => ((MoreVisualStatesViewModel) DataContext).RefreshProperties(); Ahhh No. What about converting the DataTemplate into a UserControl? Anything is worth a shot.. Though – I still suspect I’m going to have to ‘RefreshProperties’ if I want the rectangles to update. Still. No. This DataTemplate DataTrigger binding is becoming a bit of a pain… I can’t add a ‘refresh’ button to the actual code base, it’s not exactly user friendly. I’m going to end this one now, and put some investigating into the use of the DataStateSwitchBehavior (all the ones I’ve found, well, all 2 of them are working in SL3, but not 4…)

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• SSRS 2008 R2 KPIs with bullet graphs

  Key Performance Indicators are typically displayed in a scorecard with stop light indicators, which are either red, amber or green light icons. The limitation for these kind of indicators is that you can see the actual and target values in two different fields as well as see the status of the KPI in red, amber or green color. If the user wants to figure out the thresholds associated with the KPI, these values are generally not visible. Further, representing the threshold values in the scorecard itself defeats the purpose of the scorecard. The scorecard should display the KPI's status in the most summarized form and use a minimal amount of space on the dashboard. In this tip we would look at how to address this issue.

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• Migrating users and IIS settings from a workgroup win2k3 machine to a new win2k8r2

  - by amber

  I am retiring my old Windows Server 2003 Standard 32bit machine to a new machine with Windows Server 2008 R2 Standard. The two sticking points are migrating user accounts (and there are a lot of them) and IIS settings/websites (again, there are a lot). The new machine has not been provisioned yet. I'm at that point where I'm about install the OS on it. The old machibe is configured with a mirrored set for its OS and data partitions. I have broken the mirror set, replicated all of the data to an external drive, and then rebuilt the mirror set. In short, I have an image of the old machine to play with while safely leaving it up and running. Thanks!

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• HP DAT72x6 autoloader

  - by ericmayo

  Hoping someone here has seen this similar issue and can offer soem advise... I have an HP DAT72x6 auto loader tape backup unit. The external kind, here is a link to an owner's manual I found of it. http://www.dectrader.com/docs/set2/emr_na-c00070400-1.pdf I purchased the unit used about 6 months ago. The unit stopped working after 3-4 back-ups, it's used one day a month to do a monthly backup of another system. Suffice it to say the unit gets very little usage. There is an amber light on the front of the unit called the OAR (Operator Attention Required). The manual states to call for service when this light comes on and stays on. I've tried a few things to resolve but none are working. I've tried power cycling, re-securing the SCSI cables at both ends. Unit was used so I didn't pay much ($500) and so I don't want to spend a lot to have it fixed; might as well buy something new one if fixing this is going to cost more than $100-$150 bucks. I'm curious to see if anyone here has been around these devices or possibly is an HP repair person that can give me some things to try to resolve. The manual states that a solid amber OAR light indicates a hardware failure. When I power cycle the unit I see one of two scenarios so far. The unit powers up, shows self test in the LCD, then LCD changes to show all possible images and the OAR light comes on. The unit powers up, LCD is completely blank, the green lights go through some sort of process of going on and off and later the amber OAR light comes on and stays on. If it's a simple misalignment issue, I may be able to fix myself but not knowing what could cause the OAR light to come on gives me no where to even start. Google around gave no help either. I hoping someone here has experience with this and can help or point me in the right direction. Also, I don't have the HP Diagnostic tools mentioned in many manuals. The unit is connected to a Linux box. The 3-4 backups I've done with it so far have had no issues. We run amanda backup. Before this incident the unit was backing up and reading tapes fine. Thanks for any help or suggestions.

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• How to use NUnit GUI with a C#/ASP.NET website?

  - by Amber Shah

  I have a C#/ASP.NET website that has some code (*.cs) files in the App_Code directory. I would like to test them using NUnit. I have written a test file with the proper [TestFixture] and [Test] annotations and have put it here: App_Code/Test/TestClassName.cs. I load up the NUnit GUI to run it but it wants me to select a .exe or .dll file. There is none in the bin folder of my project. My project does successfully run and is built and everything, but still no exe or dll file. How can I get the NUnit Gui to just run the test in that class?

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• Continuous Deployment with a C#/ASP.NET website?

  - by Amber Shah

  I have a website in C#/ASP.NET that is currently in development. When we are in production, I would like to do releases frequently over the course of the day, as we fix bugs and add features (like this: http://toni.org/2010/05/19/in-praise-of-continuous-deployment-the-wordpress-com-story/). If you upload a new version of the site or even change a single file, it kicks out the users that are currently logged in and makes them start over any forms and such. Is there a secret to being able to do deployments without interfering with users for .NET sites?

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• o write a C++ program to encrypt and decrypt certain codes.

  - by Amber

  Step 1: Write a function int GetText(char[],int); which fills a character array from a requested file. That is, the function should prompt the user to input the filename, and then read up to the number of characters given as the second argument, terminating when the number has been reached or when the end of file is encountered. The file should then be closed. The number of characters placed in the array is then returned as the value of the function. Every character in the file should be transferred to the array. Whitespace should not be removed. When testing, assume that no more than 5000 characters will be read. The function should be placed in a file called coding.cpp while the main will be in ass5.cpp. To enable the prototypes to be accessible, the file coding.h contains the prototypes for all the functions that are to be written in coding.cpp for this assignment. (You may write other functions. If they are called from any of the functions in coding.h, they must appear in coding.cpp where their prototypes should also appear. Do not alter coding.h. Any other functions written for this assignment should be placed, along with their prototypes, with the main function.) Step 2: Write a function int SimplifyText(char[],int); which simplifies the text in the first argument, an array containing the number of characters as given in the second argument, by converting all alphabetic characters to lower case, removing all non-alpha characters, and replacing multiple whitespace by one blank. Any leading whitespace at the beginning of the array should be removed completely. The resulting number of characters should be returned as the value of the function. Note that another array cannot appear in the function (as the file does not contain one). For example, if the array contained the 29 characters "The 39 Steps" by John Buchan (with the " appearing in the array), the simplified text would be the steps by john buchan of length 24. The array should not contain a null character at the end. Step 3: Using the file test.txt, test your program so far. You will need to write a function void PrintText(const char[],int,int); that prints out the contents of the array, whose length is the second argument, breaking the lines to exactly the number of characters in the third argument. Be warned that, if the array contains newlines (as it would when read from a file), lines will be broken earlier than the specified length. Step 4: Write a function void Caesar(const char[],int,char[],int); which takes the first argument array, with length given by the second argument and codes it into the third argument array, using the shift given in the fourth argument. The shift must be performed cyclicly and must also be able to handle negative shifts. Shifts exceeding 26 can be reduced by modulo arithmetic. (Is C++'s modulo operations on negative numbers a problem here?) Demonstrate that the test file, as simplified, can be coded and decoded using a given shift by listing the original input text, the simplified text (indicating the new length), the coded text and finally the decoded text. Step 5: The permutation cypher does not limit the character substitution to just a shift. In fact, each of the 26 characters is coded to one of the others in an arbitrary way. So, for example, a might become f, b become q, c become d, but a letter never remains the same. How the letters are rearranged can be specified using a seed to the random number generator. The code can then be decoded, if the decoder has the same random number generator and knows the seed. Write the function void Permute(const char[],int,char[],unsigned long); with the same first three arguments as Caesar above, with the fourth argument being the seed. The function will have to make up a permutation table as follows: To find what a is coded as, generate a random number from 1 to 25. Add that to a to get the coded letter. Mark that letter as used. For b, generate 1 to 24, then step that many letters after b, ignoring the used letter if encountered. For c, generate 1 to 23, ignoring a or b's codes if encountered. Wrap around at z. Here's an example, for only the 6 letters a, b, c, d, e, f. For the letter a, generate, from 1-5, a 2. Then a - c. c is marked as used. For the letter b, generate, from 1-4, a 3. So count 3 from b, skipping c (since it is marked as used) yielding the coding of b - f. Mark f as used. For c, generate, from 1-3, a 3. So count 3 from c, skipping f, giving a. Note the wrap at the last letter back to the first. And so on, yielding a - c b - f c - a d - b (it got a 2) e - d f - e Thus, for a given seed, a translation table is required. To decode a piece of text, we need the table generated to be re-arranged so that the right hand column is in order. In fact you can just store the table in the reverse way (e.g., if a gets encoded to c, put a opposite c is the table). Write a function called void DePermute(const char[],int,char[], unsigned long); to reverse the permutation cypher. Again, test your functions using the test file. At this point, any main program used to test these functions will not be required as part of the assignment. The remainder of the assignment uses some of these functions, and needs its own main function. When submitted, all the above functions will be tested by the marker's own main function. Step 6: If the seed number is unknown, decoding is difficult. Write a main program which: (i) reads in a piece of text using GetText; (ii) simplifies the text using SimplifyText; (iii) prints the text using PrintText; (iv) requests two letters to swap. If we think 'a' in the text should be 'q' we would type aq as input. The text would be modified by swapping the a's and q's, and the text reprinted. Repeat this last step until the user considers the text is decoded, when the input of the same letter twice (requesting a letter to be swapped with itself) terminates the program. Step 7: If we have a large enough sample of coded text, we can use knowledge of English to aid in finding the permutation. The first clue is in the frequency of occurrence of each letter. Write a function void LetterFreq(const char[],int,freq[]); which takes the piece of text given as the first two arguments (same as above) and returns in the 26 long array of structs (the third argument), the table of the frequency of the 26 letters. This frequency table should be in decreasing order of popularity. A simple Selection Sort will suffice. (This will be described in lectures.) When printed, this summary would look something like v x r s z j p t n c l h u o i b w d g e a q y k f m 168106 68 66 59 54 48 45 44 35 26 24 22 20 20 20 17 13 12 12 4 4 1 0 0 0 The formatting will require the use of input/output manipulators. See the header file for the definition of the struct called freq. Modify the program so that, before each swap is requested, the current frequency of the letters is printed. This does not require further calls to LetterFreq, however. You may use the traditional order of regular letter frequencies (E T A I O N S H R D L U) as a guide when deciding what characters to exchange. Step 8: The decoding process can be made more difficult if blank is also coded. That is, consider the alphabet to be 27 letters. Rewrite LetterFreq and your main program to handle blank as another character to code. In the above frequency order, space usually comes first.

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• Continuous Deployment with an ASP.NET website?

  - by Amber Shah

  I have a website in C#/ASP.NET that is currently in development. When we are in production, I would like to do releases frequently over the course of the day, as we fix bugs and add features (like this: http://toni.org/2010/05/19/in-praise-of-continuous-deployment-the-wordpress-com-story/). If you upload a new version of the site or even change a single file, it kicks out the users that are currently logged in and makes them start over any forms and such. Is there a secret to being able to do deployments without interfering with users for .NET sites?

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• Write a C++ program to encrypt and decrypt certain codes.

  - by Amber

  Step 1: Write a function int GetText(char[],int); which fills a character array from a requested file. That is, the function should prompt the user to input the filename, and then read up to the number of characters given as the second argument, terminating when the number has been reached or when the end of file is encountered. The file should then be closed. The number of characters placed in the array is then returned as the value of the function. Every character in the file should be transferred to the array. Whitespace should not be removed. When testing, assume that no more than 5000 characters will be read. The function should be placed in a file called coding.cpp while the main will be in ass5.cpp. To enable the prototypes to be accessible, the file coding.h contains the prototypes for all the functions that are to be written in coding.cpp for this assignment. (You may write other functions. If they are called from any of the functions in coding.h, they must appear in coding.cpp where their prototypes should also appear. Do not alter coding.h. Any other functions written for this assignment should be placed, along with their prototypes, with the main function.) Step 2: Write a function int SimplifyText(char[],int); which simplifies the text in the first argument, an array containing the number of characters as given in the second argument, by converting all alphabetic characters to lower case, removing all non-alpha characters, and replacing multiple whitespace by one blank. Any leading whitespace at the beginning of the array should be removed completely. The resulting number of characters should be returned as the value of the function. Note that another array cannot appear in the function (as the file does not contain one). For example, if the array contained the 29 characters "The 39 Steps" by John Buchan (with the " appearing in the array), the simplified text would be the steps by john buchan of length 24. The array should not contain a null character at the end. Step 3: Using the file test.txt, test your program so far. You will need to write a function void PrintText(const char[],int,int); that prints out the contents of the array, whose length is the second argument, breaking the lines to exactly the number of characters in the third argument. Be warned that, if the array contains newlines (as it would when read from a file), lines will be broken earlier than the specified length. Step 4: Write a function void Caesar(const char[],int,char[],int); which takes the first argument array, with length given by the second argument and codes it into the third argument array, using the shift given in the fourth argument. The shift must be performed cyclicly and must also be able to handle negative shifts. Shifts exceeding 26 can be reduced by modulo arithmetic. (Is C++'s modulo operations on negative numbers a problem here?) Demonstrate that the test file, as simplified, can be coded and decoded using a given shift by listing the original input text, the simplified text (indicating the new length), the coded text and finally the decoded text. Step 5: The permutation cypher does not limit the character substitution to just a shift. In fact, each of the 26 characters is coded to one of the others in an arbitrary way. So, for example, a might become f, b become q, c become d, but a letter never remains the same. How the letters are rearranged can be specified using a seed to the random number generator. The code can then be decoded, if the decoder has the same random number generator and knows the seed. Write the function void Permute(const char[],int,char[],unsigned long); with the same first three arguments as Caesar above, with the fourth argument being the seed. The function will have to make up a permutation table as follows: To find what a is coded as, generate a random number from 1 to 25. Add that to a to get the coded letter. Mark that letter as used. For b, generate 1 to 24, then step that many letters after b, ignoring the used letter if encountered. For c, generate 1 to 23, ignoring a or b's codes if encountered. Wrap around at z. Here's an example, for only the 6 letters a, b, c, d, e, f. For the letter a, generate, from 1-5, a 2. Then a - c. c is marked as used. For the letter b, generate, from 1-4, a 3. So count 3 from b, skipping c (since it is marked as used) yielding the coding of b - f. Mark f as used. For c, generate, from 1-3, a 3. So count 3 from c, skipping f, giving a. Note the wrap at the last letter back to the first. And so on, yielding a - c b - f c - a d - b (it got a 2) e - d f - e Thus, for a given seed, a translation table is required. To decode a piece of text, we need the table generated to be re-arranged so that the right hand column is in order. In fact you can just store the table in the reverse way (e.g., if a gets encoded to c, put a opposite c is the table). Write a function called void DePermute(const char[],int,char[], unsigned long); to reverse the permutation cypher. Again, test your functions using the test file. At this point, any main program used to test these functions will not be required as part of the assignment. The remainder of the assignment uses some of these functions, and needs its own main function. When submitted, all the above functions will be tested by the marker's own main function. Step 6: If the seed number is unknown, decoding is difficult. Write a main program which: (i) reads in a piece of text using GetText; (ii) simplifies the text using SimplifyText; (iii) prints the text using PrintText; (iv) requests two letters to swap. If we think 'a' in the text should be 'q' we would type aq as input. The text would be modified by swapping the a's and q's, and the text reprinted. Repeat this last step until the user considers the text is decoded, when the input of the same letter twice (requesting a letter to be swapped with itself) terminates the program. Step 7: If we have a large enough sample of coded text, we can use knowledge of English to aid in finding the permutation. The first clue is in the frequency of occurrence of each letter. Write a function void LetterFreq(const char[],int,freq[]); which takes the piece of text given as the first two arguments (same as above) and returns in the 26 long array of structs (the third argument), the table of the frequency of the 26 letters. This frequency table should be in decreasing order of popularity. A simple Selection Sort will suffice. (This will be described in lectures.) When printed, this summary would look something like v x r s z j p t n c l h u o i b w d g e a q y k f m 168106 68 66 59 54 48 45 44 35 26 24 22 20 20 20 17 13 12 12 4 4 1 0 0 0 The formatting will require the use of input/output manipulators. See the header file for the definition of the struct called freq. Modify the program so that, before each swap is requested, the current frequency of the letters is printed. This does not require further calls to LetterFreq, however. You may use the traditional order of regular letter frequencies (E T A I O N S H R D L U) as a guide when deciding what characters to exchange. Step 8: The decoding process can be made more difficult if blank is also coded. That is, consider the alphabet to be 27 letters. Rewrite LetterFreq and your main program to handle blank as another character to code. In the above frequency order, space usually comes first.

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• Gallery has too much padding in IE7

  - by Amber

  My Flickr gallery looks good in all browsers except IE 7. What else do I need to put in my CSS code for it to not look so lopsided in IE 7. I added the display: block but it didn't do anything. a img { display: block; *display: inline-block; float: left; border: none; padding: 3px; background-color: #fff; border: 1px solid green; margin-right: 15px; margin-bottom: 15px; } Right now it looks like this. Is there something I'm doing wrong with the CSS? Should I be adding in something for IE so it can read it properly? This is my site

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• HTML5 Playlist plays 2 videos, How about 4 or 5?

  - by amber

  I'm able to get two videos to play sequentially, (and without pause!) with this code from Apple, (see section 2-4)... http://developer.apple.com/safari/library/documentation/AudioVideo/Conceptual/Using_HTML5_Audio_Video/ControllingMediaWithJavaScript/ControllingMediaWithJavaScript.html ...Yet completely lost as to how to play a 3rd or 5th video. Trouble is I'm a Javascript noob :-(, so if you figure this out please share as much of your code as possible. Thanks much!

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• How to change the position of a imageButton when onClick

  - by Amber

  I am trying to shift the position of a image button when on click. I tried the following but it crashes at "rlOut.addView(imgP, p);" I have no issues when running them in onCreate(). RelativeLayout.LayoutParams p = new RelativeLayout.LayoutParams(62, 62); ImageButton imgP = (ImageButton)findViewById(R.id.imgP); public boolean onTouch(View v, MotionEvent event) { // TODO Auto-generated method stub LayoutParams par = (LayoutParams)imbBtn.getLayoutParams(); if(event.getAction()==MotionEvent.ACTION_DOWN) { Log.d("ok","down"); mX = (int) event.getX() - imbBtn.getWidth() / 2; mY = (int) event.getY() - imbBtn.getHeight() / 2; et1.setText("mX down: "+String.valueOf(mX)); et2.setText("mY down: "+String.valueOf(mY)); } else if (event.getAction()==MotionEvent.ACTION_UP) { Log.d("ok","up"); p.leftMargin=mX; p.rightMargin=mY; rlOut.addView(imgP, p); Log.d("ok","p"); }

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• HP Envy dv6t-7300: Disabled WiFi through button and can't enable it anymore

  - by Mateus B. Cassiano

  Well, I have a HP Envy dv6t-7300 laptop that came with a Ralink RT5390 WiFi card. Everything was working perfectly, and eventually I press the WiFi button in my keyboard to toggle the card on/off. Until today, all worked right: if the wifi was off (wifi LED amber) and I press the wifi button, after a few seconds the LED turn white and everything works. If I repeat the process, the wifi LED turn amber and the card get disabled, but now, I can't turn it on anymore. running sudo rfkill list all I get: 0: phy0: Wireless LAN Soft blocked: no Hard blocked: no 1: hp-wifi: Wireless LAN Soft blocked: no Hard blocked: yes So, I ran sudo rfkill unblock all but nothing changed. As a side note, if I run sudo ifconfig wlan0 up, the indicator LED gets white (indicating that the card was enabled), but Ubuntu still say that the card is blocked by hardware. Extra information: the card works without issues in windows and in Ubuntu installer (booting from a live CD). I'm using the card out-of-box, using the drivers already included in Ubuntu 12.10. The module rt2800pci is loaded and working fine, not blacklisted, etc, etc. The card and the button toggle worked flawlessly until today, when I toggled it off and can't turn it on anymore... The problem is back, but in a different manner: if I don't press the wifi key a few times during the grub loading, in the login screen the wifi button will be ambar (disabled), pressing it will toggle it white (enabled) or ambar (disabled) again, but ubuntu still says that the network card was disabled by hardware and doesn't connect... In other words, if I don't press the WiFi button a few times when Ubuntu is booting, it will be stuck with the "network card was disabled by hardware" message, even if the light is white (enabled). Any clue? Maybe a error in some startup script or config file?

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• poblems with jquery code

  - by Michael

  Another jquery issue... I have tried this several times using "class" and "id" elements and I can not get it right. I am hoping the brains on stackoverflow can help! The problem that I am having is when I open the page all elments are closed. When I click on one link all links open. I believe it closes correctly the problem is that when I open the first link all items open. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Bid Items</title> <link href="bid.css" rel="stylesheet" type="text/css" /> <script src="jquerry/js/jquery.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function(){ $('#showhideconent').hide(); $('a').click(function(){ $('#showhideconent').show('slow'); }); $('a#close').click(function(){ $('#showhideconent').hide('slow'); }) }); $(document).ready(function(){ $('#showhideconent2').hide(); $('a').click(function(){ $('#showhideconent2').show('slow'); }); $('a#close2').click(function(){ $('#showhideconent2').hide('slow'); }) }); $(document).ready(function(){ $('#showhideconent3').hide(); $('a').click(function(){ $('#showhideconent3').show('slow'); }); $('a#close3').click(function(){ $('#showhideconent3').hide('slow'); }) }); $(document).ready(function(){ $('#showhideconent4').hide(); $('a').click(function(){ $('#showhideconent4').show('slow'); }); $('a#close4').click(function(){ $('#showhideconent4').hide('slow'); }) }); </script> </head> <body class="oneColElsCtr" onload="MM_preloadImages('Assignment4b.jpg')"> <div id="container"> <div id="mainContent"> <h1>Bid Page</h1> <h1>Coke Memorbila</h1> <a href="#" id="click">Amber Bottle 1914</a> <div id="box" align="center"> <div id="showhideconent"> <p><a href="coke/Amber1914.shtml"><img src="amber1914.jpg" width="200" height="200" alt="Amber Coke" /></a></p> <p><a href="#" id="close">Close</a> </p> </div> </div> <a href="#" id="click">Amber Bottle 1915</a> <div id="box" align="center"> <div id="showhideconent2"> <p><a href="coke/Amber1915.shtml"><img src="coke/Amber1914.shtml" width="200" height="200" alt="Amber Bottle 1915" /></a></p> <p><a href="#" id="close2">Close</a> </p> </div> </div> <a href="#" id="click">Green 1929</a> <div id="box" align="center"> <div id="showhideconent3"> <p><a href="coke/green1929.shtml"><img src="green1929.jpg" width="200" height="200" alt="Green 1929" /></a></p> <p><a href="#" id="close3">Close</a> </p> </div> </div> <a href="#" id="click">1970s Cans</a> <div id="box" align="center"> <div id="showhideconent4"> <p><a href="coke/tincans.shtml"><img src="coke_tincan.jpg" width="200" height="200" alt="Tin Cans" /></a></p> <p><a href="#" id="close4">Close</a> </p> </div> </div> </body> </html>

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• MySQL: Count occurrences of known (or enumerated) distinct values

  - by Eilidh

  After looking at how to count the occurrences of distinct values in a field, I am wondering how to count the occurrences of each distinct value if the distinct values are known (or enumerated). For example, if I have a simple table - TrafficLight Colour ------------ ------ 1 Red 2 Amber 3 Red 4 Red 5 Green 6 Green where one column (in this case Colour) has known (or enumerated) distinct values, how could I return the count for each colour as a separate value, rather than as an array, as in the linked example. To return an array with a count of each colour (using the same method as in the linked example), the query would be something like SELECT Colour COUNT(*) AS ColourCount FROM TrafficLights GROUP BY Colour, and return an array - Colour ColourCount ------ ----------- Red 3 Amber 1 Green 2 What I would like to do is to return the count for each Colour AS a separate total (e.g. RedCount). How can I do this?

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• How should I evaluate new browser languages?

  - by Andrea

  In these days there are many projects whose aim is to bring new languages to the browser by compiling them to JavaScript. Among the others one can mention ClojureScript, CoffeScript, Dart, haXe, Emscripten, Amber Smalltalk. I'd like to try a few of these out, but I am not sure what I should be looking for when evaluating these languages to see if they are suitable for production. How should I evaluate a new browser language, and what are the pitfalls I should be looking for?

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• How to configure SCSI hard drives and RAID for Poweredge 2850 web server

  - by Saul

  I'm trying to set up a Poweredge 2850 as a web server, but as a server novice it's causing me some confusion. Its a virgin install so no data to be lost as yet, so I'd like to get the best arrangement for setting up Windows Server 2008. The box will run IIS, a mail and FTP server. The current physical arrangement of the hot swap drives is 1 73GB 3 146GB 5 blank 0 73GB 2 146GB 4 146GB (but flashes green, amber off) When I enter the PERC config screens on boot up I've got Raid Ch- 0 ID 0 ONLIN A00-00 1 ONLIN A00-01 2 ONLIN A01-00 3 ONLIN A01-01 4 HOTSP I think that drives 0 and 1 are set to RAID 1 and drives 2 and 3 are also set to RAID 1, certainly I can see 2 logical drives, both raid 1 of 69880MB and 139900MB Now what I think I am getting here is that the 2 73GB drives mirror each other and the 2 146GB drives mirror 2? so by my noob thinking if a drive fails I can pull it, insert and new one and it will reduplicate from its matching pair? I think the flashing amber probably indicates a failing drive in slot 4, should that just be binned? What confuses me coming from a home user XP background is that when I load up Windows Server 2008 OS under my computer I only see a C drive of about 70GB capacity. i.e wheres the 146GB drive? Any advice appreciated

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• Wake-on-lan only works so many times

  - by Chance

  I have Wake-on-lan configured on my Windows XP machine so that the computer will wake up from Standby. Waking the computer from Standby via network traffic seems to work a certain number of times, say 4 or 5, then it stops working. If I restart the computer it seems to reset this behavior so that I can use WOL a few more times before it starts working. I use the command "wol" on my other, Linux machine with the appropriate IP address and MAC address of the card. I looked at the network card to see if it had different lights when WOL worked and when it didn't. When it has a solid amber light where the ethernet cable connects, WOL seems to work. When it has a flashing amber light, WOL does not. It seems that the system seems to almost "shut off" the card when it falls to sleep, but I don't know if this is a function of time or number of standby/wakeups. I have a 3Com 3c920 network card. If I look at the properties in Device Manager, I have "Allow this Device to bring the Computer out of Standby" checked. In the Advanced tab I have anything related to RWU (Remote Wake Up) enabled. I also believe I have the appropriate settings in BIOS related to Remote Wake-Up and I have tried both S1 and S3 power configurations in the BIOS. Intuitively, I would think I would uncheck "Allow the Computer to turn off this device to save power", but doing so disables the "Allow this Device to bring the Computer out of Standby" option. Does anyone know what is happening here or if there is a way to fix it? I have an integrated network card; would getting one that goes into a slot be better? I am running Windows XP on a Dell Optiplex GX240 with a 3Com 3c920 network card.

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• How to parametrize WPF Style?

  - by Konstantin

  Hi! I'm looking for a simplest way to remove duplication in my WPF code. Code below is a simple traffic light with 3 lights - Red, Amber, Green. It is bound to a ViewModel that has one enum property State taking one of those 3 values. Code declaring 3 ellipses is very duplicative. Now I want to add animation so that each light fades in and out - styles will become even bigger and duplication will worsen. Is it possible to parametrize style with State and Color arguments so that I can have a single style in resources describing behavior of a light and then use it 3 times - for 'Red', 'Amber' and 'Green' lights? <UserControl.Resources> <l:TrafficLightViewModel x:Key="ViewModel" /> </UserControl.Resources> <StackPanel Orientation="Vertical" DataContext="{StaticResource ViewModel}"> <StackPanel.Resources> <Style x:Key="singleLightStyle" TargetType="{x:Type Ellipse}"> <Setter Property="StrokeThickness" Value="2" /> <Setter Property="Stroke" Value="Black" /> <Setter Property="Height" Value="{Binding Width, RelativeSource={RelativeSource Self}}" /> <Setter Property="Width" Value="60" /> <Setter Property="Fill" Value="LightGray" /> </Style> </StackPanel.Resources> <Ellipse> <Ellipse.Style> <Style TargetType="{x:Type Ellipse}" BasedOn="{StaticResource singleLightStyle}"> <Style.Triggers> <DataTrigger Binding="{Binding State}" Value="Red"> <Setter Property="Fill" Value="Red" /> </DataTrigger> </Style.Triggers> </Style> </Ellipse.Style> </Ellipse> <Ellipse> <Ellipse.Style> <Style TargetType="{x:Type Ellipse}" BasedOn="{StaticResource singleLightStyle}"> <Style.Triggers> <DataTrigger Binding="{Binding State}" Value="Amber"> <Setter Property="Fill" Value="Red" /> </DataTrigger> </Style.Triggers> </Style> </Ellipse.Style> </Ellipse> <Ellipse> <Ellipse.Style> <Style TargetType="{x:Type Ellipse}" BasedOn="{StaticResource singleLightStyle}"> <Style.Triggers> <DataTrigger Binding="{Binding State}" Value="Green"> <Setter Property="Fill" Value="Green" /> </DataTrigger> </Style.Triggers> </Style> </Ellipse.Style> </Ellipse> </StackPanel>

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• Twitter Typeahead only shows only 5 results

  - by user3685388

  I'm using the Twitter Typeahead version 0.10.2 autocomplete but I'm only receiving 5 results from my JSON result set. I can have 20 or more results but only 5 are shown. What am I doing wrong? var engine = new Bloodhound({ name: "blackboard-names", prefetch: { url: "../CFC/Login.cfc?method=Search&returnformat=json&term=%QUERY", ajax: { contentType: "json", cache: false } }, remote: { url: "../CFC/Login.cfc?method=Search&returnformat=json&term=%QUERY", ajax: { contentType: "json", cache: false }, }, datumTokenizer: Bloodhound.tokenizers.obj.whitespace('value'), queryTokenizer: Bloodhound.tokenizers.whitespace }); var promise = engine.initialize(); promise .done(function() { console.log("done"); }) .fail(function() { console.log("fail"); }); $("#Impersonate").typeahead({ minLength: 2, highlight: true}, { name: "blackboard-names", displayKey: 'value', source: engine.ttAdapter() }).bind("typeahead:selected", function(obj, datum, name) { console.log(obj, datum, name); alert(datum.id); }); Data: [ { "id": "1", "value": "Adams, Abigail", "tokens": [ "Adams", "A", "Ad", "Ada", "Abigail", "A", "Ab", "Abi" ] }, { "id": "2", "value": "Adams, Alan", "tokens": [ "Adams", "A", "Ad", "Ada", "Alan", "A", "Al", "Ala" ] }, { "id": "3", "value": "Adams, Alison", "tokens": [ "Adams", "A", "Ad", "Ada", "Alison", "A", "Al", "Ali" ] }, { "id": "4", "value": "Adams, Amber", "tokens": [ "Adams", "A", "Ad", "Ada", "Amber", "A", "Am", "Amb" ] }, { "id": "5", "value": "Adams, Amelia", "tokens": [ "Adams", "A", "Ad", "Ada", "Amelia", "A", "Am", "Ame" ] }, { "id": "6", "value": "Adams, Arik", "tokens": [ "Adams", "A", "Ad", "Ada", "Arik", "A", "Ar", "Ari" ] }, { "id": "7", "value": "Adams, Ashele", "tokens": [ "Adams", "A", "Ad", "Ada", "Ashele", "A", "As", "Ash" ] }, { "id": "8", "value": "Adams, Brady", "tokens": [ "Adams", "A", "Ad", "Ada", "Brady", "B", "Br", "Bra" ] }, { "id": "9", "value": "Adams, Brandon", "tokens": [ "Adams", "A", "Ad", "Ada", "Brandon", "B", "Br", "Bra" ] } ]

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• HP Proliant Servers - WMI query for system health

  - by Mike McClelland

  Hi, I want to query lots of HP servers to determine their overall health. I don't want to use any packages, or even SNMP - I want to query the server health from WMI and understand if a box is Green/Amber/Red - just like the HP Management Home Page. This MUST be possible - but I can't find any documentation... Oh yes, and the servers are running Windows Server 2003/8. Help!! Mike

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• Why does my monitor have a black screen but the power light is blinking green?

  - by Chris Vesper

  I have a ViewSonic VA912b 19" display I use as a secondary monitor. When I turn it on, the power light is green for a few seconds, and then switches to blinking green. The display stays black. Windows thinks the monitor is on, as it shows up in the control panel as a second monitor. If I unplug the DVI cable, it displays a "No Signal" message and the power light goes to amber, which means it went to sleep.

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• HP Pavilion tx2000 - Wifi adapter no longer works after moving from 12.04 to a 12.10 clean install

  - by Marek L.

  I have a HP Pavilion tx2000 that I have been running Ubuntu 12.04 on for a couple of months without any problems (wifi worked great) until yesterday when my hard drive failed. I replaced the hard drive and decided to install Ubuntu 12.10. Unlike 12.04, the wifi did not work after the installation finished and all the updates where installed (over Ethernet). The network drop down in the top right didn't even show a wireless option. I Googled about for a bit and found some solutions that seemed like they might work. Unfortunately they did not. Here is what I tried: sudo apt-get remove bcmwl-kernel-source sudo apt-get install b43-fwcutter sudo apt-get install firmware-b43-lpphy-installer Restart the computer. And the wifi still didn't work. At which point I panicked a bit and tried to undo the previous commands by running: sudo apt-get remove b43-fwcutter firmware-b43-lpphy-installer sudo apt-get install bcmwl-kernel-source Restart the computer. The wifi still doesn't work. This is where I stopped because I have no idea what I am doing and don't want to mess something up. The network drop down still doesn't show a wireless option and the hardware wifi switch on the laptop is amber (it turns blue when the wifi is on). Using the hardware switch does not change the color. Output from: sudo lspci ... 08:00.0 Network controller: Broadcom Corporation BCM4322 802.11a/b/g/n Wireless LAN Controller (rev 01) ... Output from: sudo lshw -class network *-network UNCLAIMED description: Network controller product: BCM4322 802.11a/b/g/n Wireless LAN Controller vendor: Broadcom Corporation physical id: 0 bus info: pci@0000:08:00.0 version: 01 width: 64 bits clock: 33MHz capabilities: pm msi pciexpress bus_master cap_list configuration: latency=0 resources: memory:d1100000-d1103fff ... Output from: sudo rfkill list all 0: hp-wifi: Wireless LAN Soft blocked: no Hard blocked: yes UPDATE: After writing up this question tried the following command: sudo rfkill unblock all At first it didn't do anything but after running it about four times, sudo rfkill list all now returns: 0: hp-wifi: Wireless LAN Soft blocked: no Hard blocked: no But the network menu still does not have a wireless option and the hardware switch still glows amber. Pushing the hardware switch turns the hard block back on and I have to run sudo rfkill unblock all multiple times again to turn it off. Any help is appreciated! Update 2: Full output from sudo lspci -nn: 00:00.0 Host bridge [0600]: Advanced Micro Devices [AMD] RS780 Host Bridge [1022:9600] 00:01.0 PCI bridge [0604]: Advanced Micro Devices [AMD] RS780/RS880 PCI to PCI bridge (int gfx) [1022:9602] 00:04.0 PCI bridge [0604]: Advanced Micro Devices [AMD] RS780/RS880 PCI to PCI bridge (PCIE port 0) [1022:9604] 00:05.0 PCI bridge [0604]: Advanced Micro Devices [AMD] RS780/RS880 PCI to PCI bridge (PCIE port 1) [1022:9605] 00:06.0 PCI bridge [0604]: Advanced Micro Devices [AMD] RS780 PCI to PCI bridge (PCIE port 2) [1022:9606] 00:11.0 SATA controller [0106]: Advanced Micro Devices [AMD] nee ATI SB7x0/SB8x0/SB9x0 SATA Controller [AHCI mode] [1002:4391] 00:12.0 USB controller [0c03]: Advanced Micro Devices [AMD] nee ATI SB7x0/SB8x0/SB9x0 USB OHCI0 Controller [1002:4397] 00:12.1 USB controller [0c03]: Advanced Micro Devices [AMD] nee ATI SB7x0 USB OHCI1 Controller [1002:4398] 00:12.2 USB controller [0c03]: Advanced Micro Devices [AMD] nee ATI SB7x0/SB8x0/SB9x0 USB EHCI Controller [1002:4396] 00:13.0 USB controller [0c03]: Advanced Micro Devices [AMD] nee ATI SB7x0/SB8x0/SB9x0 USB OHCI0 Controller [1002:4397] 00:13.1 USB controller [0c03]: Advanced Micro Devices [AMD] nee ATI SB7x0 USB OHCI1 Controller [1002:4398] 00:13.2 USB controller [0c03]: Advanced Micro Devices [AMD] nee ATI SB7x0/SB8x0/SB9x0 USB EHCI Controller [1002:4396] 00:14.0 SMBus [0c05]: Advanced Micro Devices [AMD] nee ATI SBx00 SMBus Controller [1002:4385] (rev 3a) 00:14.1 IDE interface [0101]: Advanced Micro Devices [AMD] nee ATI SB7x0/SB8x0/SB9x0 IDE Controller [1002:439c] 00:14.2 Audio device [0403]: Advanced Micro Devices [AMD] nee ATI SBx00 Azalia (Intel HDA) [1002:4383] 00:14.3 ISA bridge [0601]: Advanced Micro Devices [AMD] nee ATI SB7x0/SB8x0/SB9x0 LPC host controller [1002:439d] 00:14.4 PCI bridge [0604]: Advanced Micro Devices [AMD] nee ATI SBx00 PCI to PCI Bridge [1002:4384] 00:14.5 USB controller [0c03]: Advanced Micro Devices [AMD] nee ATI SB7x0/SB8x0/SB9x0 USB OHCI2 Controller [1002:4399] 00:18.0 Host bridge [0600]: Advanced Micro Devices [AMD] Family 11h Processor HyperTransport Configuration [1022:1300] (rev 40) 00:18.1 Host bridge [0600]: Advanced Micro Devices [AMD] Family 11h Processor Address Map [1022:1301] 00:18.2 Host bridge [0600]: Advanced Micro Devices [AMD] Family 11h Processor DRAM Controller [1022:1302] 00:18.3 Host bridge [0600]: Advanced Micro Devices [AMD] Family 11h Processor Miscellaneous Control [1022:1303] 00:18.4 Host bridge [0600]: Advanced Micro Devices [AMD] Family 11h Processor Link Control [1022:1304] 01:05.0 VGA compatible controller [0300]: Advanced Micro Devices [AMD] nee ATI RS780M/RS780MN [Mobility Radeon HD 3200 Graphics] [1002:9612] 08:00.0 Network controller [0280]: Broadcom Corporation BCM4322 802.11a/b/g/n Wireless LAN Controller [14e4:432b] (rev 01) 09:00.0 Ethernet controller [0200]: Realtek Semiconductor Co., Ltd. RTL8111/8168B PCI Express Gigabit Ethernet controller [10ec:8168] (rev 02)

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